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If the pole is on level ground then you have the outline of a right angled triangle with an opposite side of 3 feet and an adjacent angle of 30 degrees. To find the length of the adjacent side (which in effect is the shadow of the pole) use the tangent ratio: tangent = opposite/adjacent which can be rearranged to: adjacent = opposite/tangent adjacent = 3/tangent 30o = 5.196152423 feet Therefore the shadow cast by the pole is 5.2 feet corrected to one decimal place.

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In addition to the height of the object, the length of its shadow depends on a few other things that are not described in the question. -- Is the object standing straight upright ? -- Is the shadow cast on the ground or on sometheing else? -- If on the ground, is the ground level ? -- What is the altitude (angle) of the sun ?


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Related Questions

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About how long is a shadow of an 80 ft tall oak tree if the angle of the sun is 40 degrees?

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