D=duck P=pig
D+P=19
2D+4P=52
Therefore there are 12 ducks and 7 pigs.
If all were ducks there would be ony 36 legs. The extra 14 legs must represent 7 horses, which with 11 ducks would have 7 x 4 + 11 x 2 ie 28 + 22 ie 50 legs as stated.
That would be 20 legs in total.
38
There are 12 pigs 15 ducks have 30 legs 102 legs - 30 legs = 72 legs. Pigs have four legs, ducks have two legs 72 legs divided by 6 = 12 12 ducks having 24 legs 12 pigs having 48 legs 24 + 24 + 30 = 102
8 pigs & 9 ducks
15 Ducks
Two ducks have a total of eight legs, with each duck having four legs each.
Ducks have 2 legs.
ducks have 2 legs ducks have 2 legs
If all were ducks there would be ony 36 legs. The extra 14 legs must represent 7 horses, which with 11 ducks would have 7 x 4 + 11 x 2 ie 28 + 22 ie 50 legs as stated.
That would be 20 legs in total.
38
Let G be the number of goats and D be the number of ducks. We can set up a system of equations based on the number of heads and legs: G + D = 99 (from heads) and 4G + 2D = 296 (from legs). Solving this system of equations, we find that there are 33 goats and 66 ducks.
Two ducks have a total of 4 legs and two dogs have a total of 8 legs. Therefore, 2 ducks and 2 dogs have a total of 12 legs.
There are 12 pigs 15 ducks have 30 legs 102 legs - 30 legs = 72 legs. Pigs have four legs, ducks have two legs 72 legs divided by 6 = 12 12 ducks having 24 legs 12 pigs having 48 legs 24 + 24 + 30 = 102
8 pigs & 9 ducks
I don't think any do to be honest...