D=duck P=pig
D+P=19
2D+4P=52
Therefore there are 12 ducks and 7 pigs.
If all were ducks there would be ony 36 legs. The extra 14 legs must represent 7 horses, which with 11 ducks would have 7 x 4 + 11 x 2 ie 28 + 22 ie 50 legs as stated.
That would be 20 legs in total.
38
There are 12 pigs 15 ducks have 30 legs 102 legs - 30 legs = 72 legs. Pigs have four legs, ducks have two legs 72 legs divided by 6 = 12 12 ducks having 24 legs 12 pigs having 48 legs 24 + 24 + 30 = 102
8 pigs & 9 ducks
Ducks have 2 legs.
Two ducks have a total of eight legs, with each duck having four legs each.
ducks have 2 legs ducks have 2 legs
Let G be the number of goats and D be the number of ducks. We can set up a system of equations based on the number of heads and legs: G + D = 99 (from heads) and 4G + 2D = 296 (from legs). Solving this system of equations, we find that there are 33 goats and 66 ducks.
If all were ducks there would be ony 36 legs. The extra 14 legs must represent 7 horses, which with 11 ducks would have 7 x 4 + 11 x 2 ie 28 + 22 ie 50 legs as stated.
That would be 20 legs in total.
Two ducks have a total of 4 legs and two dogs have a total of 8 legs. Therefore, 2 ducks and 2 dogs have a total of 12 legs.
38
Well, well, well, looks like we've got a little math puzzle on our hands. If we let D be the number of ducks and C be the number of cows, we have the lovely equations D + C = 35 and 2D + 4C = 110. Solving this system of equations, we find that there are 15 ducks waddling around causing a ruckus in the yard.
There are 12 pigs 15 ducks have 30 legs 102 legs - 30 legs = 72 legs. Pigs have four legs, ducks have two legs 72 legs divided by 6 = 12 12 ducks having 24 legs 12 pigs having 48 legs 24 + 24 + 30 = 102
8 pigs & 9 ducks
12