There are 60 such numbers.
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
15 of them.
To be irrational, it would have to have an infinite number of digits, without a periodic repetition.
Six (6)
With repetition, the smallest is 22222 and the largest is 88888 Without repetition, the smallest is 23458 and the largest is 85432
33 = 27 with repetition, 3! = 3*2*1 = 6 without repetition.
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
15 of them.
9876543210
30 without repetition (6P2) 66 with repetition (12C2)
To be irrational, it would have to have an infinite number of digits, without a periodic repetition.
Six (6)
With repetition, the smallest is 22222 and the largest is 88888 Without repetition, the smallest is 23458 and the largest is 85432
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
repetition
To calculate the number of four-digit numbers that can be made using the digits 1, 4, 5, and 9 without repetition, we use the permutation formula. Since there are 4 digits to choose from for the first digit, 3 for the second, 2 for the third, and 1 for the fourth, the total number of permutations is 4 x 3 x 2 x 1 = 24. Therefore, there are 24 different four-digit numbers that can be formed using the digits 1, 4, 5, and 9 without repetition.
Pi is 3.141592654 it is an irrational number (meaning it will have infinite number of digits to the right of the decimal point, without repetition)