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Assuming two 6-sided die, there are 36 possible outcomes. 3 of them {(1-1),(1-2),(2-1)} are equal to 3 or less, so the rest of them are greater than 3.

Therefore the probability is 33/36 = 11/12, or about 91.67% chance.

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Q: If two dice are rolled find the probability of getting a sum greater than 3?
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