Assuming two 6-sided die, there are 36 possible outcomes. 3 of them {(1-1),(1-2),(2-1)} are equal to 3 or less, so the rest of them are greater than 3.
Therefore the probability is 33/36 = 11/12, or about 91.67% chance.
It is 15/36 = 5/12
It is 5 over 6.
Assuming these are regular dice, the probability is 1.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
The probability is 35/36.
Two standard dice cannot have a sum greater than 12. The probability, then, of getting a sum greater than 15 is zero.
If they are normal dice, the probability is 0.
It is 15/36 = 5/12
It is 5 over 6.
Assuming these are regular dice, the probability is 1.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
The probability is 35/36.
The probability is 1, if the dice are rolled often enough.
Probably.
The probability is 8/36 or 2/9
1/12 or .083
1/12