Want this question answered?
Be notified when an answer is posted
Not necessarly. If the sum of two of the sides congruent to each other are greater than that of the sides opposite them, then no. If however the kite forms a rombus ot square, the diagnoles will form four congruent triangles with the base of both being the line of symmetry.
Any plane triangle can be divided into four congruent triangles. Find the midpoint of each side, and draw a line from each midpoint to the other two midpoints. Forgive the crude ASCII graphics: <pre> + |\ + + | \ +-+-+ original triangle + |\ +-+ |\ |\ +-+-+ divided triangle + |\ +-+ each congruent triangle </ref>
Yes * * * * * No. A median is a line from a vertex to the midpoint of the opposite side. It divides the triangle into congruent parts only if the triangle is equilateral or if the triangle is isosceles and it is the median from the unequal vertex. In all other cases the two parts will not be congruent.
If the 2 triangles are right triangles, which are congruent to slicing the rectangle on the diagonal, then arrange one on top of the rectangle, and the other to the side, so that the two hypotenuses are in line with each other. This will make a bigger right triangle, which is similar to the smaller right triangles - each side is double of the smaller triangles.
i have the same question...
Its true
Its true
Its true
Its true
Yes they both will overlap each other perfectly
The diagonal of a parallelogram divides it into two congruent triangles. This is because the diagonal creates two pairs of congruent triangles by dividing the parallelogram into two equal halves.
No because the rectangles line segments are long lines and the triangles are short ones so no the triangular prism does not have congruent line segments on the edges. Welcomes :)
Not necessarly. If the sum of two of the sides congruent to each other are greater than that of the sides opposite them, then no. If however the kite forms a rombus ot square, the diagnoles will form four congruent triangles with the base of both being the line of symmetry.
It is the line joining the midpoints of two sides of a polygon - usually a triangle. This line will be parallel to the third side. The three median-median lines will divide any triangle into 4 congruent triangles that are similar to the original.It is the line joining the midpoints of two sides of a polygon - usually a triangle. This line will be parallel to the third side. The three median-median lines will divide any triangle into 4 congruent triangles that are similar to the original.It is the line joining the midpoints of two sides of a polygon - usually a triangle. This line will be parallel to the third side. The three median-median lines will divide any triangle into 4 congruent triangles that are similar to the original.It is the line joining the midpoints of two sides of a polygon - usually a triangle. This line will be parallel to the third side. The three median-median lines will divide any triangle into 4 congruent triangles that are similar to the original.
Any plane triangle can be divided into four congruent triangles. Find the midpoint of each side, and draw a line from each midpoint to the other two midpoints. Forgive the crude ASCII graphics: <pre> + |\ + + | \ +-+-+ original triangle + |\ +-+ |\ |\ +-+-+ divided triangle + |\ +-+ each congruent triangle </ref>
Just because they look the same does not mean they are. Normally if sides are congruent they are marked by the same indicator. Which is usually a line, number, or letter. Same thing with angles, except angles would not use lines to indicate congruency. If you have any three congruent parts on triangles (the number may change due the shape) then those triangles are congruent.
In geometry, congruent line segments are segments that have the same length. When two line segments are congruent, it means they are equal in length and can be superimposed on each other perfectly. This property is fundamental in geometric constructions and proofs, as it allows for precise measurements and comparisons between different segments.