mid point of xy
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between X and Y
There appear to be 10 terms in the determinant. A determinant can only have a perfect number of terms. So something has gone wrong with the question. 1: x2 plus 1 2: xy 3: xz 4: xy 5: y2 plus 1 6: yz 7: 1 plus x2 plus y2 plus z2 8: xz 9: yz 10: z2 plus 1
10 cm
12.9
According to the laws of exponents, xy times xz = xy+z. Therefore, 27 x 22 = 2(7+2) = 29 = 512.
between X and Y
8.3
It cannot be a property since it is not generally true!
The possible combinations of pairs that can be formed using the keywords xy, xz, and yz are: xy, xz, and yz.
There appear to be 10 terms in the determinant. A determinant can only have a perfect number of terms. So something has gone wrong with the question. 1: x2 plus 1 2: xy 3: xz 4: xy 5: y2 plus 1 6: yz 7: 1 plus x2 plus y2 plus z2 8: xz 9: yz 10: z2 plus 1
Z is halfway between X and Y.
10 cm
12.9
According to the laws of exponents, xy times xz = xy+z. Therefore, 27 x 22 = 2(7+2) = 29 = 512.
2z + 5 - xz
4
xz + x + yz + y = (x + y)(z + 1)