It seems there might be a typo in your question. If you meant to ask for the value of y when x is given a specific value (like x = 8), please provide the relationship between x and y (e.g., a formula or equation) so I can help you find the value of y.
This question equates to, find x and y such that x + y = 8 x - y = 8 Solving the second equation for x: x = 8 + y Substituting in to the first equation: 8 + y + y = 8 2y = 0 y = 0 Solving for x: x - 0 = 8 x = 8. The two numbers are 8 and 0.
x = y/k: 24 = 6/k so k = ¼; when y = 8, x = 8/¼ = 32
If ( y ) varies inversely as ( x ), this means ( y = \frac{k}{x} ) for some constant ( k ). Given that ( y = 24 ) when ( x = 8 ), we can find ( k ) by substituting these values: ( 24 = \frac{k}{8} ) which gives ( k = 192 ). Now, to find ( y ) when ( x = 4 ), we use the equation ( y = \frac{192}{4} ), resulting in ( y = 48 ).
8
x+y = 10 and y = x+8 x+x+8 = 10 x+x = 10-8 2x = 2 x = 1 Substitute the value of x into the original equations to find the value of y: So: x = 1 and y = 9
if y = 5x – 8 find the value of x if y = 7
This question equates to, find x and y such that x + y = 8 x - y = 8 Solving the second equation for x: x = 8 + y Substituting in to the first equation: 8 + y + y = 8 2y = 0 y = 0 Solving for x: x - 0 = 8 x = 8. The two numbers are 8 and 0.
If y varies directly as x and if x = 2 when y = 8 then k = 4.
x = y/k: 24 = 6/k so k = ¼; when y = 8, x = 8/¼ = 32
y is 32.
y = 8
y is 12
8
x+y = 10 and y = x+8 x+x+8 = 10 x+x = 10-8 2x = 2 x = 1 Substitute the value of x into the original equations to find the value of y: So: x = 1 and y = 9
40
x+y=12 x-y =4 x=12-4 =8 8+y=12 y=12-8 =4 so x=8 y=4 8+4=12 8-4=4
2x+y = 8 y = -x+5 Substitute y for -x+5 into the first equation: 2x+(-x+5) = 8 2x-x+5 = 8 x = 8-5 x = 3 Substitute the value of x into the original equations to find the value of y: x = 3 and y = 2