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Two numbers such that their sum is 8 and their difference is also 8?
This question equates to, find x and y such that x + y = 8 x - y = 8 Solving the second equation for x: x = 8 + y Substituting in to the first equation: 8 + y + y = 8 2y = 0 y = 0 Solving for x: x - 0 = 8 x = 8. The two numbers are 8 and 0.
If x varies directly as y and x equals 24 when y equals 6 Then find x when y equals 8?
x = y/k: 24 = 6/k so k = ¼; when y = 8, x = 8/¼ = 32
If y equals x of the power of three find y when x equals 2?
8
Solve this equation using subtitution x plus y equals 10 and y equals x plus 8?
x+y = 10 and y = x+8 x+x+8 = 10 x+x = 10-8 2x = 2 x = 1 Substitute the value of x into the original equations to find the value of y: So: x = 1 and y = 9
What is y intercept and x intercept of y x plus 8?
To find the y intercept put zero in for x and solve. To find the x intercept put zero in for y and solve. (0,8) and (-8,0)
if y = 5x – 8 find the value of x if y = 7?
if y = 5x – 8 find the value of x if y = 7
Two numbers such that their sum is 8 and their difference is also 8?
This question equates to, find x and y such that x + y = 8 x - y = 8 Solving the second equation for x: x = 8 + y Substituting in to the first equation: 8 + y + y = 8 2y = 0 y = 0 Solving for x: x - 0 = 8 x = 8. The two numbers are 8 and 0.
If y varies directly as x squared find k when x 2 and y 8?
If y varies directly as x and if x = 2 when y = 8 then k = 4.
If x varies directly as y and x equals 24 when y equals 6 Then find x when y equals 8?
x = y/k: 24 = 6/k so k = ¼; when y = 8, x = 8/¼ = 32
When the value of y varies directly with x and y -16 when x -4. Find y when x 8?
y is 32.
Find an equation of variation where y varies directly as x and y equals 10 when x equals 5 find y when x is 4?
y = 8
If y varies inversely as x and y equals 24 when x equals 8 find y when x is 4?
y is 12
If y equals x of the power of three find y when x equals 2?
8
Solve this equation using subtitution x plus y equals 10 and y equals x plus 8?
x+y = 10 and y = x+8 x+x+8 = 10 x+x = 10-8 2x = 2 x = 1 Substitute the value of x into the original equations to find the value of y: So: x = 1 and y = 9
Find an equation of variation where y varies directly as x and y equals 8 when x equals 2 find y when x equals 10?
40
Find the value of 2 numbers if their sum is 12 and their difference is 4?
x+y=12 x-y =4 x=12-4 =8 8+y=12 y=12-8 =4 so x=8 y=4 8+4=12 8-4=4
How do you solve 2x plus y equals 8 y equals -x plus 5 substitution method?
2x+y = 8 y = -x+5 Substitute y for -x+5 into the first equation: 2x+(-x+5) = 8 2x-x+5 = 8 x = 8-5 x = 3 Substitute the value of x into the original equations to find the value of y: x = 3 and y = 2
