This question equates to, find x and y such that x + y = 8 x - y = 8 Solving the second equation for x: x = 8 + y Substituting in to the first equation: 8 + y + y = 8 2y = 0 y = 0 Solving for x: x - 0 = 8 x = 8. The two numbers are 8 and 0.
x = y/k: 24 = 6/k so k = ¼; when y = 8, x = 8/¼ = 32
8
x+y = 10 and y = x+8 x+x+8 = 10 x+x = 10-8 2x = 2 x = 1 Substitute the value of x into the original equations to find the value of y: So: x = 1 and y = 9
To find the y intercept put zero in for x and solve. To find the x intercept put zero in for y and solve. (0,8) and (-8,0)
if y = 5x – 8 find the value of x if y = 7
This question equates to, find x and y such that x + y = 8 x - y = 8 Solving the second equation for x: x = 8 + y Substituting in to the first equation: 8 + y + y = 8 2y = 0 y = 0 Solving for x: x - 0 = 8 x = 8. The two numbers are 8 and 0.
The answer is 5x+3y. (5 xs and 3 ys)
If y varies directly as x and if x = 2 when y = 8 then k = 4.
x = y/k: 24 = 6/k so k = ¼; when y = 8, x = 8/¼ = 32
y is 32.
y = 8
y is 12
8
x+y = 10 and y = x+8 x+x+8 = 10 x+x = 10-8 2x = 2 x = 1 Substitute the value of x into the original equations to find the value of y: So: x = 1 and y = 9
40
x+y=12 x-y =4 x=12-4 =8 8+y=12 y=12-8 =4 so x=8 y=4 8+4=12 8-4=4