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Q: If y Y when x 8 find y when X's?
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if y = 5x – 8 find the value of x if y = 7?

if y = 5x – 8 find the value of x if y = 7


Two numbers such that their sum is 8 and their difference is also 8?

This question equates to, find x and y such that x + y = 8 x - y = 8 Solving the second equation for x: x = 8 + y Substituting in to the first equation: 8 + y + y = 8 2y = 0 y = 0 Solving for x: x - 0 = 8 x = 8. The two numbers are 8 and 0.


How do you simplify x plus x plus x plus x plus y plus y plus y plus x?

The answer is 5x+3y. (5 xs and 3 ys)


If y varies directly as x squared find k when x 2 and y 8?

If y varies directly as x and if x = 2 when y = 8 then k = 4.


If x varies directly as y and x equals 24 when y equals 6 Then find x when y equals 8?

x = y/k: 24 = 6/k so k = ¼; when y = 8, x = 8/¼ = 32


When the value of y varies directly with x and y -16 when x -4. Find y when x 8?

y is 32.


Find an equation of variation where y varies directly as x and y equals 10 when x equals 5 find y when x is 4?

y = 8


If y varies inversely as x and y equals 24 when x equals 8 find y when x is 4?

y is 12


If y equals x of the power of three find y when x equals 2?

8


Solve this equation using subtitution x plus y equals 10 and y equals x plus 8?

x+y = 10 and y = x+8 x+x+8 = 10 x+x = 10-8 2x = 2 x = 1 Substitute the value of x into the original equations to find the value of y: So: x = 1 and y = 9


Find an equation of variation where y varies directly as x and y equals 8 when x equals 2 find y when x equals 10?

40


Find the value of 2 numbers if their sum is 12 and their difference is 4?

x+y=12 x-y =4 x=12-4 =8 8+y=12 y=12-8 =4 so x=8 y=4 8+4=12 8-4=4