arccos(0) = 90 + 360.n (n is an element of the integers) and 90 and 360 are in degrees.
Therefore if the answer is in the subset 0<x<360 or something similar, Then the answer is 90.
cos(125) = cos(180 - 55) = cos(180)*cos(55) + sin(180)*sin(55) = -cos(55) since cos(180) = -1, and sin(180) = 0 So A = 55 degrees.
This site is not suitable for graphs.
It is pi radians wide. The end point is arbitrary.
cos x equals cos -x because cos is an even function. An even function f is such that f(x) = f(-x).
One solution. (cos x)2 - 2cos x = 3 Factor: (cos x - 3)(cos x + 1)= 0 cos x = {-1, 3} Solve: For cos x = -1, x = 180 deg No solution for cos x = 3
cos(125) = cos(180 - 55) = cos(180)*cos(55) + sin(180)*sin(55) = -cos(55) since cos(180) = -1, and sin(180) = 0 So A = 55 degrees.
This site is not suitable for graphs.
It is pi radians wide. The end point is arbitrary.
cot x = (cos x) / (sin x) cos (x - 180) = cos x cos 180 + sin x sin 180 = - cos x sin (x - 180) = sin x cos 180 - cos x sin 180 = - sin x cot (x - 180) = (cos (x - 180)) / (sin (x - 180)) = (- cos x) / (- sin x) = (cos x) / (sin x) = cot x
Cos(x) equals zero at 90 degrees and 270 degrees. If x exceeds 360 degrees, cos(x) will equal zero at any increment of 90 + 180(n) degrees. In radians, this is equivalent to (pi/2) + pi(n) radians.
y = cos ( x ). z = cos ( x + 180 degrees ).
cos x equals cos -x because cos is an even function. An even function f is such that f(x) = f(-x).
the answer is 180 degrees; since cos 180⁰ = -1, then cos-1 -1 = 180⁰ mathematically cos-1-1 here calculator is required and you'll get answer 180 degrees.....
2 x cosine squared x -1 which also equals cos (2x)
One solution. (cos x)2 - 2cos x = 3 Factor: (cos x - 3)(cos x + 1)= 0 cos x = {-1, 3} Solve: For cos x = -1, x = 180 deg No solution for cos x = 3
When x = 75.964 degrees plus or minus any multiple of 180 degrees.
Let angle A be opposite side a and between sides b and c; using the cosine rule you can find each angle:a² = b² + c² - 2bc cos A→ A = arc cos((b² + c² - a²)/2bc)→ Angles are:arc cos((2.85² + 4.7² - 2.6²)/(2 × 2.85 × 4.7)) ≈ 28.9°arc cos((2.6² + 4.7² - 2.85²)/(2 × 2.6 × 4.7)) ≈ 32.0°arc cos((2.6² + 2.85² - 4.7²)/(2 × 2.6 × 2.85)) ≈ 119.1°Note that the third angle can also be worked out form 180° - (28.9° + 32.0°) = 180° - 60.1° = 119.1°Area triangle = ½bc sin A ≈ ½ × 2.85 × 4.7 × sin(28.9°) ≈ 3.24 cm²