1 in 5.45 of picking at least 2 blue marbles
any 2 from 3 is 3
correct picks =3X7(red)=21 of 2 blue only
1 pick of 3 blue only
any 3 from 10=120
120/22=5.45
well blue would b picked 65percent of the time an purple would be 25 and ten percent would be yellow
There would be a 7/19 or 36.84% chance of drawing a blue marble from the bag.
If one card is picked at random from a normal deck of cards, the probability is 20/52 or 5/13.
That would depend on how many yellow and blue marbles are in a pack. If yellow and blue marbles are sold separately and there are the same number of marbles in a pack, buy one of each. That's probably not the case.
14/42. You have to add the amount of marbles and then put the probabilityof answers you're looking for. Ex: 14 white marbles 28 red marbles 14+28=42 ?/42 your looking for the probability of white marbles, so you put in the amount of white marbles on the fraction. =14/42
well blue would b picked 65percent of the time an purple would be 25 and ten percent would be yellow
There would be a 7/19 or 36.84% chance of drawing a blue marble from the bag.
196/5513, or about .0356=3.56%AssumptionI assume that you are asking what is the probability that the first three coins picked out of the pot are nickels. Obviously the answer would be different if, for example, you are asking what is the probability that if you pick all of the coins out of the pot what is the probability that at some point in picking out coins you will pick three nickels in a row.ExplanationP(three nickels in a row)=P(first coin picked is a nickel)*P(second coin picked is a nickel given that first coin picked is a nickel)*P(third coin picked is a nickel given that first two coins picked are nickels)=(50/150)*(49/149)*(48/148)=196/5513, or about .0356=3.56%
70
If by them you mean your eyeballs then yes. I suppose one would go blind if you picked your eyes off your eyesockets.
If one card is picked at random from a normal deck of cards, the probability is 20/52 or 5/13.
The density of 10 marbles would depend on the material the marbles are made of. Generally, marbles have a density ranging from 2.5 to 2.75 grams per cubic centimeter. So, the total density of 10 marbles would be the density of one marble multiplied by 10.
33
If you had a bag of marbles, and there were two colours - red and green - and the ratio of the coloured marbles is two times the amount of green marbles to red marbles, you would have a ratio of 2:1
135 degrees.
You would be more likely to pull out a white marble as there are no red marbles in the bag.
There are 8 marbles in the bag, and 6 are green, so the chance that the first one you pick is green is 6/8 or .75. Let's call the event where you pick the green marble first, G, for green of course. Now since you picked a marble there are only 7 left. If you picked a green one then the chances of picking a purple one are now 2/7 since there are two purple marbles and seven total marbles. Let's call the event of picking the purple marble F, (I was going to use P but we need that letter for probability. Purple is a fine color so I picked F.) Now we use the conditional probability rule that tells us what is the chance of picking purple given that we already picked green. The symbol P(F|G) means probability of event F given that event G has already happened. P(F|G)= (the probability of picking green and purple)/ (probability of picking green.) We know these from above. G=6/8 and If we pick a green, probability of picking a purple is 2/7 so we multiply these to get probability of picking both and we have 6/8x2/7 or 12/56. So 12/56=(Probability of Picking green and purple)/( probability of picking green). We have 12/56=[P(G and F)]/(6/8) we want P(G and F) so we multiply 12/56x 6/8 and we have 72/448 So the answer is : 72/448 or about .16 (NOTE: this would be a totally different problem if we took out the first marble then put it back. It is important to be sure what is being asked. If you replaced the marble, the problem is much easier. It is simply 6/8 x 2/8 =12/64 or 3/16) Some people have trouble remembering or understanding the conditional probability rule. I will take just a second to explain it in the hopes it will make it easier to use and remember. The multiplication rule says if we have two mutually exclusive events, A and B, the probability of A and B is P(A)xP(B), so if we want event A to occur THEN event B, we have P(A)xP(B|A) which means probability of A multiplied by probability of B given A has already happened. This equal probability of A and B so we have: P(A)xP(B|A)=P(A and B) . Now divide by P(A) and we have: P(B|A)=P(A and B)/P(A). This is the way the rule is usually stated. Note: P(A|B)=P(A and B)/P(B).