In this problem, think of it as being able to select 0-9 for each of the 4 numbers. So, you can select 10*10*10*10 = 10,000 combinations. If you could not use a number twice, it would be 10*9*8*7.
That depends entirely on the number of digits each number is permitted to have !
By making a number tree that could have as many as 1,000,000 combos.
1. The numbers 1 through 99 are 99 different numbers; each one occurs once.
575757
There are 360 of them.
there are 63 combos
That depends entirely on the number of digits each number is permitted to have !
By making a number tree that could have as many as 1,000,000 combos.
120, if you use each number once.
1. The numbers 1 through 99 are 99 different numbers; each one occurs once.
"Please may I have two number 6 combos?"
575757
You go through smaller numbers to see which can go into your number without remainder.You go through smaller numbers to see which can go into your number without remainder.You go through smaller numbers to see which can go into your number without remainder.You go through smaller numbers to see which can go into your number without remainder.
3.5 3.6 3.7 3.8 3.9 many different combos
Square numbers have an odd number of factors.
Different elements have different numbers of protons. The number of protons identifies the element.
Yes. Isotopes have the same atomic number because all of their atoms have the same number of protons. They have different mass numbers because their atoms have different numbers of neutrons, and mass number is the sum of the numbers of protons and neutrons.