25
Revision: Sounds like 4 teams would play while one team would sit out, so that would make 5 weeks for each time. Guess there would be something like 16 different outcomes without the "bye" week/game and with the "bye" week/game that could freely move into any week/game the outcomes would bump up to 80. 25 just didn't sound right.
305,175 revision: 2 to the 15th is 32,768 combinations.
I assume you mean that each team plays only one game, for a total of five games. There are 32 possible outcomes. add-on: No, I think he/she means 10 nfl games not teams. That would be 20 teams in all. It'd probably be 2 to the 10th.. which makes it like 1024 possible outcomes.
To represent all possible combinations of tossing a coin and drawing a card from a standard deck, you need to consider both events. Tossing a coin has 2 outcomes (heads or tails), and drawing a card from a standard deck has 52 outcomes. Therefore, the total number of combinations is 2 (coin outcomes) multiplied by 52 (card outcomes), resulting in 104 leaves on the tree diagram.
To determine the number of leaves on a tree diagram representing all possible combinations of tossing a coin and drawing a card from a standard deck of cards, we first note that there are 2 possible outcomes when tossing a coin (heads or tails) and 52 possible outcomes when drawing a card. Therefore, the total number of combinations is 2 (coin outcomes) multiplied by 52 (card outcomes), resulting in 104 leaves on the tree diagram.
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305,175 revision: 2 to the 15th is 32,768 combinations.
Four outcomes, three combinations.
I assume you mean that each team plays only one game, for a total of five games. There are 32 possible outcomes. add-on: No, I think he/she means 10 nfl games not teams. That would be 20 teams in all. It'd probably be 2 to the 10th.. which makes it like 1024 possible outcomes.
IF YOU HAVE ONE GAME, YOU HAVE A POSIBILITY OF 3 OUTCOMES, IF YOU HAVE 2 GAMES IT GO'S UP TO 9 POSIBILE OUTCOMES. FIRST ANSWER 1X3=3 SECOND IS 3X3=9 FOR 10 GAMES IT IS 3X3 TEN TIMES 3X3X3X3X3X3X3X3X3X3=59,049 POSSIBLE COMBINATIONS (I THINK)HA HA
26 = 32 different combos. revision: 2 to the 6th is 64 different combos.
32,768 different outcomes
There are 6 outcomes with one roll and 6^2 with two and 6^3 with three. So the answer is 216.
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3 + 3 + 3 + 3 + 3 = 15 total possible outcomes. You can 'prove' this by laying out a table of possibles where a user might tick the result of each game..... Match....1....2....3....4....5 Win......._...._...._...._...._ Lose......_...._...._...._...._ Draw....._...._...._...._...._
Since there are two teams, and ten games, there are 20 possible outcomes, since either team may win each game.
It is called the faculty of 3 and written 3! 3! = 3 * 2 * 1 The same for 4! = 4*3*2*1 and so on...
To represent all possible combinations of tossing a coin and drawing a card from a standard deck, you need to consider both events. Tossing a coin has 2 outcomes (heads or tails), and drawing a card from a standard deck has 52 outcomes. Therefore, the total number of combinations is 2 (coin outcomes) multiplied by 52 (card outcomes), resulting in 104 leaves on the tree diagram.