25
Revision: Sounds like 4 teams would play while one team would sit out, so that would make 5 weeks for each time. Guess there would be something like 16 different outcomes without the "bye" week/game and with the "bye" week/game that could freely move into any week/game the outcomes would bump up to 80. 25 just didn't sound right.
305,175 revision: 2 to the 15th is 32,768 combinations.
I assume you mean that each team plays only one game, for a total of five games. There are 32 possible outcomes. add-on: No, I think he/she means 10 nfl games not teams. That would be 20 teams in all. It'd probably be 2 to the 10th.. which makes it like 1024 possible outcomes.
-8
It is used for lots of things such as finding out the total possible outcomes of tossing coins. You find the line that corresponds with how many coins you toss and add all the numbers in that line to get the number of possible outcomes also you can use it to find combinations and permutations and triangular numbers
25. In one throw the odds are 2/8. That is, th ere are 8 possible outcomes, two of which are considered "winning" combinations (HHH and TTT). In 100 throws, you would expect each of the 8 outcomes to occur 12 or 13 times (the average of the number of times each of the 8 outcomes occurs will always be exactly 12.5, whether the distribution is even or whether you got all heads all 100 throws and all the other combinations were zero). You would expect the number of times you get all heads or all tails - two of those combinations - to be 25.
305,175 revision: 2 to the 15th is 32,768 combinations.
Four outcomes, three combinations.
I assume you mean that each team plays only one game, for a total of five games. There are 32 possible outcomes. add-on: No, I think he/she means 10 nfl games not teams. That would be 20 teams in all. It'd probably be 2 to the 10th.. which makes it like 1024 possible outcomes.
IF YOU HAVE ONE GAME, YOU HAVE A POSIBILITY OF 3 OUTCOMES, IF YOU HAVE 2 GAMES IT GO'S UP TO 9 POSIBILE OUTCOMES. FIRST ANSWER 1X3=3 SECOND IS 3X3=9 FOR 10 GAMES IT IS 3X3 TEN TIMES 3X3X3X3X3X3X3X3X3X3=59,049 POSSIBLE COMBINATIONS (I THINK)HA HA
26 = 32 different combos. revision: 2 to the 6th is 64 different combos.
32,768 different outcomes
There are 6 outcomes with one roll and 6^2 with two and 6^3 with three. So the answer is 216.
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3 + 3 + 3 + 3 + 3 = 15 total possible outcomes. You can 'prove' this by laying out a table of possibles where a user might tick the result of each game..... Match....1....2....3....4....5 Win......._...._...._...._...._ Lose......_...._...._...._...._ Draw....._...._...._...._...._
Since there are two teams, and ten games, there are 20 possible outcomes, since either team may win each game.
It is called the faculty of 3 and written 3! 3! = 3 * 2 * 1 The same for 4! = 4*3*2*1 and so on...
A lot