The answer is Length 4 and Width -8.
Area = (length) x (width)72 = (24) x (width)Width = 72/24 = 3Perimeter = 2 x (length + width) = 2 x (24 + 3) = 2 x (27) = 54
The length should be 6cm and the width is 4cm.
length + width = ½ perimeter ie 24', so length = 24 - width length = 2 x width + 3, so 24 - width = 2 x width + 3 ie 21 = 3 x width so width = 7 and length = 17
The area of a hexagon with a perimeter of 24 feet is about 41.6 square feet.
divide perimeter by 6.
Perimeter = 24 inches Area = 35 square inches
Area = 8*24 =192 square feet Perimeter = 24+24+8+8 = 64 feet
Perimeter= 2(l+b) =2*39 =78m = Area =l*b = =24*15 =360m
Area = (length) x (width)72 = (24) x (width)Width = 72/24 = 3Perimeter = 2 x (length + width) = 2 x (24 + 3) = 2 x (27) = 54
If that's a rectangle, the perimeter is 24 inches and the area is 27 square inches.
384 square feet 16 X 24 =384..............lenght X width =sq ...lenght x width x height = cubic
length----8cm breadth---4cm
The length should be 6cm and the width is 4cm.
perimeter 24 so length + width half of that ie 12. Length 3 times width must be 9 and width 3.
To find the perimeter of a shape with an area of 480 square feet, you first need to know the shape's dimensions. For example, if you consider a rectangle, the area can be calculated as length multiplied by width (A = length × width). If you take a rectangle with dimensions of 20 feet by 24 feet, the perimeter would be 2(length + width) = 2(20 + 24) = 88 feet. Other shapes will yield different perimeters for the same area depending on their dimensions.
6 feet... area 24 perimeter 20
length + width = ½ perimeter ie 24', so length = 24 - width length = 2 x width + 3, so 24 - width = 2 x width + 3 ie 21 = 3 x width so width = 7 and length = 17