Then using Pythagoras' theorem:102+112 = 221 and the square root of this is the length of the hypotenuse which is 14.866 units to 3 decimal places
55A = ab/2
56 square units
It is 13 units in length
It is 39 units in length
39 sq. unitsThe area of any right triangle is A = 1/2 (b x h)1/2 (base) multiplied by (height)A right triangle can always be set down so that the legs are the base and the height.So if you know the length of the legs, you can apply the area formula directly.
A right triangle with legs of 7 and 11 units has a hypotenuse of: 13.04 units.
55A = ab/2
56 square units
Find the length of the hypotenuse of a right triangle whose legs are 8 and 15 units in length.
Length of the hypotenuse of a right triangle having legs of 1 unit each is the square root of 2 units, 1.4142 units.
The length of the hypotenuse of a right triangle with legs of lengths 5 and 12 units is: 13The length of a hypotenuse of a right triangle with legs with lengths of 5 and 12 is: 13
218.08 square units
It is 13 units in length
It is 39 units in length
10(radical "2") units, or about 14.1 units.
A = leg1leg2/2 = (8)(12)/2 = 48
39 sq. unitsThe area of any right triangle is A = 1/2 (b x h)1/2 (base) multiplied by (height)A right triangle can always be set down so that the legs are the base and the height.So if you know the length of the legs, you can apply the area formula directly.