0.2884615
The answer depends on how many cards are drawn, whether or not at random, from an ordinary deck of cards, with or without replacement. The probability for a single card, drawn at random, from a normal deck of playing cards is 1/4.
The probability of getting a face card or a red card in a standard deck of 52 cards is (26 + 12 - 3) in 52 or 35 in 52 or about 0.6731.26 red cards, 12 face cards, and 3 red cards that are also face cards.
If you randomly pick a card from a standard deck of cards, that probability will be 1/4, since 1/4 of the cards are heart.
There are 3 face cards in a suit of 13 cards, so the probability is = 3/13.
There are an equal number of cards for each suit (13 for each), and 52 cards in a deck. Therefore, your odds of selecting one card of any specific suit will always be 13 to 52, or 1 in 4 (a 25% chance).
The answer depends on how many cards are drawn, whether or not at random, from an ordinary deck of cards, with or without replacement. The probability for a single card, drawn at random, from a normal deck of playing cards is 1/4.
A deck of cards has 52 cards (not counting jokers which are optional). so if you draw one card at random you have one chance in 52 of getting a specific card. 1/52 = 1.923%
number of queen card = 4 number of cards in a deck of cards = 52 Probability of getting a queen card = 4/52 or 1/13
The probability of getting a face card or a red card in a standard deck of 52 cards is (26 + 12 - 3) in 52 or 35 in 52 or about 0.6731.26 red cards, 12 face cards, and 3 red cards that are also face cards.
If you randomly pick a card from a standard deck of cards, that probability will be 1/4, since 1/4 of the cards are heart.
pr(success) = number_of_ways_of_success/total_number_of_ways. As the two selections are independent, multiply the probability that the first card is a heart by the probability the second card is a heart. There are 13 hearts and 52 cards in a deck → pr(1st card heart) = 13/52 = 1/4 After 1 card has been selected, there are 51 cards left and if the first was a heart, there are only 12 hearts left → pr(2nd card heart also) = 12/51 = 4/17 → pr(1st two heart) = pr(1st card heart) × pr(2nd card heart) = 1/4 × 4/17 = 1/17
There are 3 face cards in a suit of 13 cards, so the probability is = 3/13.
depends on the amount of black cards there is in the pack
There are an equal number of cards for each suit (13 for each), and 52 cards in a deck. Therefore, your odds of selecting one card of any specific suit will always be 13 to 52, or 1 in 4 (a 25% chance).
That depends on which card you are getting. There are some cards called "black cards" that have no limit, but they are for millionaires and celebrities basically.
The probability of getting a red card out of a standard 52 card deck is 26 in 52, or 0.5. The probability of getting a second red card is 25 in 51, or 0.490, because one red card is missing, and the deck is short by one card. The probability of getting a black card next is 26 in 50, or 0.52, because the deck is short by two cards, but all the black cards are there. Multiply these probabilities together, and you get about 0.127, or about 1 in 8, so the probability of getting 2 red cards and then a black card in a random 52 card deck is about 1 in 8.
There are 52 cards in a deck. 1/4 are hearts. 3 are heart faces. So the probability of drawing one card that is a heart face is 3/52. The chance of drawing a face card as one card, and a heart as another is 1/4(heart)*3/13(face)=3/52 as well