40% decrease
If one's speed changes from 10 km/h to 6 km/h, one has decelerated.
distance (km) / speed (kph) = time (Hrs) if you go 1 km at 10 kph then: 1 / 10 = 0.1 but 0.1 hours isn't very helpful so: 0.1 X 60 = 6 it takes 6 minuets to go 1 kilometre at 10 kilometres per hour!
Sir, your question is not complete. Please complete the format and I might answer it
To calculate the time it takes to travel 33 km at a speed of 6 km/h, you can use the formula: time = distance ÷ speed. So, time = 33 km ÷ 6 km/h = 5.5 hours. Therefore, it will take 5.5 hours to travel that distance at the given speed.
It is 3 x 10^6 km or 3 x 106 km
If one's speed changes from 10 km/h to 6 km/h, one has decelerated.
Yes, a decrease in speed from 10 km/h to 6 km/h represents a negative acceleration, also known as deceleration or retardation. This means that the velocity is decreasing over time.
6 km/h
average speed = total_distance/total_time = (80 km + 100 km)/(10 min + 20 min) = 180 km/30 min = 6 km/min 1 hr = 60 min → 6 km/min = 6 × 60 km/h = 360 km/h
You cover 100 km in one hour. 10 km is 1/10 of 100 km, so you need 1/10 of an hour = 6 minutes.
The total distance covered by the plane is 80km + 100km = 180km, and the total time taken is 10 minutes + 20 minutes = 30 minutes. Therefore, the average speed of the plane is 180km / 30 minutes = 6 km per minute.
distance (km) / speed (kph) = time (Hrs) if you go 1 km at 10 kph then: 1 / 10 = 0.1 but 0.1 hours isn't very helpful so: 0.1 X 60 = 6 it takes 6 minuets to go 1 kilometre at 10 kilometres per hour!
Sir, your question is not complete. Please complete the format and I might answer it
To calculate the time it takes to travel 33 km at a speed of 6 km/h, you can use the formula: time = distance ÷ speed. So, time = 33 km ÷ 6 km/h = 5.5 hours. Therefore, it will take 5.5 hours to travel that distance at the given speed.
Moving 12 km in 40 minutesMoving 6 km in 15 minutesMoving 10 km in 20 minutesMoving 18 km in 30 minutesThat’s the answer!
It is 3 x 10^6 km or 3 x 106 km
Toni's average speed is 15 km h-1. As we measured her travel distance over one sixth of an hour, her speed in km h-1 is (6 X 2.5) km h-1 In phsics dont you have to change it so its meters of seconds?