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In 5 card poker find the probability of being dealt 2 pair give your answer to the eight decimal?
Jayden1
Sounds like a homework/test question.
We can find an exact answer to this question. There are (52c5) = 2598960 total combinations of five card Poker hands. We are interested in the ones where we are dealt two pair.
Let's count all the hands that have two pair and no more than two pair (quads or full house). Each pair has (4c2) = 6 forms. Of the 13 ranks there (13c2) = 78 ways to select the two pair. Once both pairs are selected there are 44 cards left for the remaining card. So there are 78 *6 *6 * 44 = 123552 hands with two pair.
In decimal form simply for 123552 / 2598960 = 4.7539015606242497614e-02 or about a 4.8% chance.
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