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n1 = 3
n2 = 3(3) + 2 = 9 + 2 = 11
n3 = 3(11) +2 = 33 + 2 = 35
n4 = 3(35) + 2 = 105 + 2 = 107

The fourth term in the sequence (n4) is 107.

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Q: In a sequence of numbers the first number is 3 and each number after the first is 2 more than 3 times the preceding number What is the fourth term in the sequence?
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