You said between, that means not including either 27 or 42. So 'between' 27 and 29, there is one integer(28). 29-27 = 2, which is one more than the # of integers between. So subtract (42-27) and that will be one more than the integers between.
They are consecutive odd integers: 25 and 27.
26 and 27
There is no reason to give, because that's not a true statement. Examples: There is no integer between 4 and 5, or between 27 and 28, or between 792 and 793.
The numbers are 13 and 14.
Do you mean which 2 integers the square root of 27 falls between? If so, then the square root of 27 is 3*sqrt3, or about 5.2. So between 5 and 6.
They lie between the integers -6 and +6.
2 & 6
-6 and -5, or 5 and 6.
27 & 28
Try squaring different integers (hint: in this case, the integers will be fairly small). If you find that the square of one integer is less than 27, and the square of the next integer is more than 27, you have your answer.
The integers are 26 and 27.
Since 27 is between 25 and 36, then √27 is between √25 and √36. So √27 is between 5 and 6, which are two consecutive numbers.
You said between, that means not including either 27 or 42. So 'between' 27 and 29, there is one integer(28). 29-27 = 2, which is one more than the # of integers between. So subtract (42-27) and that will be one more than the integers between.
They are consecutive odd integers: 25 and 27.
The two consecutive integers that have a sum of 53 are 26 and 27.
761 is a prime number, so it has only two divisors; 1 and 761 itself. 729 is the square of 27 and 784 is the square of 28. 761 is found between the numbers 729 and 784 so √761 is a number between 27 and 28 which are consecutive integers. Answer is 27 and 28