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Open the compass to a width greater than half the length of AB.Place the compass point at A.Draw arcs above and below the line AB.Move the compass point to B WITHOUT changing the compass setting.Draw arcs above and below AB to intersect them at X and Y.Join XY.XY is the perpendicular bisector of AB.7. Celebrate the successful completion of the task!
Set a compass to draw a circle with a radius that's more than half the length of the line segment but less than the whole length.Put the compass point at one end of the segment and draw an arc above the middle of the segment and another below the middle of the segment.Put the compass point at the other end of the segment and again draw arcs above and below the middle of the segment, intersecting the first two arcs.Draw a line connecting the point where the two arcs intersect above the segment and the point where they intersect below the segment.That's your perpendicular bisector.
Perpendicular rays are two rays that intersect one another to form four right angles. Below is an image that shows two perpendicular rays.
6.3
It looks like the diagram below./\
It could be, but without the diagram it is not possible to be certain.
T is the midpoint of PQangle PTR = 90 degreesRS _l_ PQPT = QT
AWNSERS A. JP=KP C.XY and JK form four right angles D. XY _I_ JK F. m
Open the compass to a little more than half the distance between the two points. Draw arcs from above the line to below the line from each end. This will look a little bit like an American football. The line that goes through the pointed ends of the football is the perpendicular bisector.
Open the compass to a width greater than half the length of AB.Place the compass point at A.Draw arcs above and below the line AB.Move the compass point to B WITHOUT changing the compass setting.Draw arcs above and below AB to intersect them at X and Y.Join XY.XY is the perpendicular bisector of AB.7. Celebrate the successful completion of the task!
Set a compass to draw a circle with a radius that's more than half the length of the line segment but less than the whole length.Put the compass point at one end of the segment and draw an arc above the middle of the segment and another below the middle of the segment.Put the compass point at the other end of the segment and again draw arcs above and below the middle of the segment, intersecting the first two arcs.Draw a line connecting the point where the two arcs intersect above the segment and the point where they intersect below the segment.That's your perpendicular bisector.
That will be difficult to do since there is no diagram below.
To solve this, four steps are needed:Find the midpoint of the line segment (X, Y) which is a point on the perpendicular bisectorFind the slope m for the line segment: m = change_in_y/change_in_xFind the slope m' of the perpendicular line; the slopes of the lines are related by mm' = -1 → m' = -1/mFind the equation of the perpendicular bisector using the slope-point equation for a line passing through point (X, Y) with slope m': y - Y = m'(x - X)Have a go before reading the solution below.--------------------------------------------------------------------The midpoint of (7, 3) and (-6, 1) is at ((7 + -6)/2, (3 + 1)/2) = (1/2, 2)The slope of the line segment is: m = change_in_y/change_in_x = (1 - 3)/(-6 - 7) = -2/-13 = 2/13The slope of the perpendicular bisector is m' = -1/m = -1/(2/13) = -13/2The equation of the perpendicular bisector passing through point (X, Y) = (1/2, 2) with slope m' = -13/2 is given by:y - Y = m'(x - Y)→ y - 2 = -13/2(x - 1/2)→ 4y - 8 = -26x + 13→ 4y + 26x = 21
= parallel + perpendicular As such no, perpendicular lines do not naturally have parallel lines. However...connect the lines in the symbols below. ++ ++ And you'll have 4 perpendicular lines, and 4 parallel lines.
Perpendicular rays are two rays that intersect one another to form four right angles. Below is an image that shows two perpendicular rays.
You did not include any 'statements below'.
There is a diagram at the related link below.