Multiple
45 = 3 x 3 x 5 or 32 x 5
180 = 2 x 2 x 3 x 3 x 5 or 22 x 32 x 5
720 = 24 x 32 x 5
28 + 29 + 31 + 32 2 x 3 x 4 x 5
There are infinitely many pairs. Suppose x is any non-zero number. Let y = 32/x. Then x*y = x*(32/x) = 32 Then there are infinitely many sets of 3 numbers, of 4 numbers, etc.
32 x 5/√4 = 32 x 5/2 = 80
45 = 3 x 3 x 5 or 32 x 5
50 = 2 x 5 x 5 (or 2 x 52)
450 = 2 x 3 x 3 x 5 x 5 or 21 x 32 x 52
It is a numerical expression.
An expression is a group of constants (numbers), variables (x, y, a), and operators (+, -, *, /, ()). An example would be 9*x + 2 or (3a - 7)/5.
90 = 2 x 3 x 3 x 5 OR 2 x 32 x 5
180 = 2 x 2 x 3 x 3 x 5 or 22 x 32 x 5
Assume the expression is:4/(x + 2) + 6/(x + 5)Simplify this expression by combining the expressions altogether. Let's go step by step.Step 1: Determine the LCD of the expression.The LCD of the expression is (x + 2)(x + 5). Multiply the top and bottom of each fractional expression by whatever factor the denominator is missing!4/(x + 2) * (x + 5)/(x + 5) + 6/(x + 5) * (x + 2)/(x + 2)Step 2: Combine the expression and simplify.(4(x + 5) + 6(x + 2))/((x + 2)(x + 5))= (4x + 20 + 6x + 12)/((x + 2)(x + 5))= (10x + 32)/((x + 2)(x + 5))
To find the exponential form of the expression (2x2x2)x(2x2x2x2x2), we need to simplify the expression first and then express it in exponential form. Given expression: (2x2x2)x(2x2x2x2x2) Simplify the expression: (2x2x2) = 2^3 = 8 (2x2x2x2x2) = 2^5 = 32 Now, substitute the simplified values back into the expression: 8 x 32 = 256 Therefore, the exponential form of (2x2x2)x(2x2x2x2x2) is 256.
720 = 24 x 32 x 5
28 + 29 + 31 + 32 2 x 3 x 4 x 5