You can find the volume of a sphere by V = (4/3)*pi*r3 where r is the radius of the sphere. So in your case, the volume would be approximately 57.90583579 m3
the volume of a sphere is 4/3 (pi) r^3, so if r= 9 then volume would be approximately 3053.63m
The volume would be 1436.7550...cm^3 and so on.
You cannot convert a sphere into square metres unless you want the surface area of the sphere. The volume of a sphere would be measured in cubic metres. You would need to be more specific about exactly what you want to know.
The volume of a sphere V = ⁴⁄₃πr³ would be near enough.
To determine how many liters of oxygen is in a 40% concentration, you would need to know the total volume of the substance in question. Then, you would multiply the percentage (40%) by the total volume to find the volume of oxygen.
You can estimate the volume of oxygen generated in a plastic bag by knowing the concentration of the oxygen generated and the total volume of the bag. Multiply the concentration of oxygen by the total volume of the bag to get an estimate of the volume of oxygen generated.
You can find the volume of a sphere by V = (4/3)*pi*r3 where r is the radius of the sphere. So in your case, the volume would be approximately 57.90583579 m3
the volume of a sphere is 4/3 (pi) r^3, so if r= 9 then volume would be approximately 3053.63m
The volume would be (500pi)/3 since the formula for a sphere is (4r3pi)/3, when radius=r The volume is exactly 523.598776 cubic meters.
To find the diameter of the sphere, you must calculate the cube root of the volume. The cube root of 20 is approximately 2.71. Therefore, the diameter of the sphere is twice this value, which is approximately 5.42 units.
Density = Mass/Volume, whatever the shape. So, if the masses are the same, the density is greater when the volume id smaller. Thus the sphere, with the smaller volume has the greater density.
The volume would be 1436.7550...cm^3 and so on.
The weight of the water in a sphere that has a diameter of 1 yard would be approximately 58.52 pounds. This calculation is based on the weight of water filling a sphere of that size at standard temperature and pressure.
To find the volume of the sphere, you need to know the density of the material the sphere is made of. With just the mass provided (75 grams), you cannot calculate the volume without this additional information.
Yes it would.
I calculated the volume of the sphere to be 10 in^3.