20
y = -2x+10
Is the equation of a straight line with slope 2 and an intercept of (0,20).
Slope= -2/5 y-intercept is 20 x-intercept is 50
4x+2y = 20 2y = -4x+20 y = -2x+10
20
2x + y = 20 y = -2x + 20 Slope = -2 m=-2
y = -2x+10
Is the equation of a straight line with slope 2 and an intercept of (0,20).
Slope= -2/5 y-intercept is 20 x-intercept is 50
4x+2y = 20 2y = -4x+20 y = -2x+10
== == y = -x + 5
Slope-line form is: y = -4(x/5 + 1)
20 = 400
5x+4y = 20 4y = -5x+20 y = -5/4x+5 Therefore: slope is -5/4 and intercept is 5
5x = 20 + y Convert to the form y = mx + b y = 5x - 20 In y = mx + b, m is the slope. I'm sure you can figure it out yourself now.
5x + 4y = 204y = -5x + 20y = (-5/4)x + 5