Depends on the kind of binomials.
Case 1:
If both binomials have different terms, then use the distribution property. Each term of one binomial will multiply both terms of the other binomial. After distribution, combine like terms, and it's done.
Case 2:
If both binomials have exactly the same terms, then work as in the 1st case, or use the formula for suaring a binomial, (a ± b)2 = a2 ± 2ab + b2.
Case 3:
If both binomials have terms that only differ in sign, then work as in the 1st case, or use the formula for the sum and the difference of the two terms, (a - b)(a + b) = a2 - b2.
a3 + b3
a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
To find the sum of ( A1A2 ) and ( A3 ), you can use the formula: ( \text{Sum} = A1 \times A2 + A3 ). This formula multiplies the values of ( A1 ) and ( A2 ) together, and then adds the value of ( A3 ) to that product.
a3 + b3 = (a + b)(a2 - ab + b2)
7 terms
There following two options should work:=sum(A1:A3) or=A1+A2+A3
There following two options should work:=sum(A1:A3) or=A1+A2+A3
There following two options should work:=sum(A1:A3) or=A1+A2+A3
a3 + b3
Sum and difference of two cubes is factored this way : a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
While there are many ways of doing it, the simplest way is to use the SUM function and a range in it like this: =SUM(A1:A5)
a3+ b3 = (a + b)(a2 - ab + b2)
a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2
a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
To find the sum of ( A1A2 ) and ( A3 ), you can use the formula: ( \text{Sum} = A1 \times A2 + A3 ). This formula multiplies the values of ( A1 ) and ( A2 ) together, and then adds the value of ( A3 ) to that product.
a3 + b3 = (a + b)(a2 - ab + b2)
a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)