No, the solution of x = 4 will not be greater than nor less than 4.
0
√x > 0 when x > 0, that is when x is a positive number.
No.
' x ' = any whole number greater than ' 2 '.
By factoring: x(1-x) = 0 Therefore: x = 0 or x = 1
No, the solution of x = 4 will not be greater than nor less than 4.
It means that something is greater than some number, and smaller than some other number. For example, the solution of an inequality might state that "x" is greater than 0, and that "x" is also less than 10, in symbols: x > 0 and x < 10 Which can be written in shorthand notation as: 0 < x < 10 Note that instead of "less than" and "greater than", you might also use "less-than-or-equal" and "greater-than-or-equal", or some combination. For example: 0 < x <= 10
0
The assertion in the question is false. The result of a multiplication depends on the values. Given two numbers X and Y, if X < 0 and if Y < 0 then X*Y is greater than either; if X > 1 and if Y > 1 then X*Y is greater than either; if X < 0 and if Y > 1 then X*Y is smaller than either; if X > 1 and if Y < 0 then X*Y is smaller than either; if 0 < X < 1 and if 0 < Y < 1 then X*Y is smaller than either; If X < 0 and if 0 < Y < 1 then X*Y is greater than X but smaller than Y; If 0 < X < 1 and if Y > 1 then X*Y is greater than X but smaller than Y; If 0 < X < 1 and if Y < 0 then X*Y is smaller than X but greater than Y; If X > 1 and if 0 < Y < 1 then X*Y is smaller than X but greater than Y.
x is greater than 1.
what is c, x + 2y, x+y equal to or greater than 8, x equal to or greater than 3, y equal to or greater than 0.
The solution will be greater than the number seven.
The solution of -6x = -16 is x = 2 2/3, which is greater than -16.
√x > 0 when x > 0, that is when x is a positive number.
It is x > -4.
f(x) = (x)^ (1/2) (i.e. the square root of x)