No, 1017 is not divisible by 5. A number is divisible by 5 only if its last digit is 0 or 5. Since the last digit of 1017 is 7, it is not divisible by 5
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No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.
35 is divisible by 5 because any number that ends in 5 is divisible by 5.
Yes, 1255 is divisible by 5, and any number that ends in 5 is divisible by 5.
1017 = MXVII
-282 + (-1017) = -282 - 1017 = -1299
yes ofcourse 1017/3=339
By these factors: 1, 3, 9, 113, 339, 1017.
No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.
The factors of 1017 are: 1, 3, 9, 113, 339, 1017.
YES. 285 is divisible by 5. A number is divisible by 5 if it ends with 0 or 5
35 is divisible by 5 because any number that ends in 5 is divisible by 5.
Yes, 1255 is divisible by 5, and any number that ends in 5 is divisible by 5.
It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.
No, because 1 is not evenly divisible by 5. However, all numbers divisible by 5 are divisible by 1.
1017 = MXVII
5/5715 = 0.000874891 5 is not evenly divisible by 5715. However, 5715 is divisible by 5. (If a number ends in 5 or 0 it is divisible by 5.) 5715/5 = 1143
-282 + (-1017) = -282 - 1017 = -1299