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Q: Is 108 a product of 4?
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How could you use the product of 108 and 4 to find the product of 324 and 4?

324 = 3 x 108 324 x 4 = 3 x 108 x 4


What is the product of 4 times 27?

4x27=108


What is the product of 4 x 27 equals?

108


Where did the 3 come from in the problem finding the product oa 108 and 4 to find the product of 324 and4?

324 is 3*108


What is the partial product of 4x27?

4 x 20 = 80 4 x 7 = 28 80 + 28 = 108 4 x 27 = 108


Product of 2 numbers is 108 if 4 is one of them what is the sum of the two numbers?

To solve this problem, you would start by dividing 108 by 4, since the problem says that the product of the 4 and another number equals 108. By dividing 108 by 4, you get 27 as the second number. Now, you want the sum of the two numbers, so you add 4 and 27. The sum is 31.


How do you find the partial product of 4x27?

4 x 20 = 80 4 x 7 = 28 80 + 28 = 108 4 x 27 = 108


How could you use the product if 108 and 4 to find the product of 324 and 4?

324*4 = (3*108)*4 = 3*(108*4) So, if you knew 108*4 you could multiply that number by 3 to get the answer to 324*4. But is it not at all clear why you would do that! First of all you need to work out the fact that 324 is actually 108*3 and then, multiplying 324 by 4 is really just as easy or difficult as multiplying 432 by 3. So one more step for no real gain.


What is the sum -3 product -108?

105


What is the product of the LCM of 22 and 108?

The LCM of 108 and 22 is 1188. You can't get a "product" of one number.


What is 4 divied by 108?

4 divided by 108 is 0.037


What is the LCM of 108 and 135?

For any two counting numbers x and y:LCM(x, y) x HCF(x, y) = Product of x and yLCM(x, y) = (Product of x and y)/HCF(x, y)Here, we have 108 and 135 & their product = 108 x 135But, HCF(108, 135) = ?So, we shall first calculate HCF by the method of prime factorization.108 = 33x22 & 135 = 33x51It is clear that 33 is the HCF of 108 and 135.So, LCM(108, 135) = (108 x 135)/33 = 4 x 135 = 540