4x27=108
108
4 x 20 = 80 4 x 7 = 28 80 + 28 = 108 4 x 27 = 108
To solve this problem, you would start by dividing 108 by 4, since the problem says that the product of the 4 and another number equals 108. By dividing 108 by 4, you get 27 as the second number. Now, you want the sum of the two numbers, so you add 4 and 27. The sum is 31.
324*4 = (3*108)*4 = 3*(108*4) So, if you knew 108*4 you could multiply that number by 3 to get the answer to 324*4. But is it not at all clear why you would do that! First of all you need to work out the fact that 324 is actually 108*3 and then, multiplying 324 by 4 is really just as easy or difficult as multiplying 432 by 3. So one more step for no real gain.
324 = 3 x 108 324 x 4 = 3 x 108 x 4
4x27=108
108
324 is 3*108
4 x 20 = 80 4 x 7 = 28 80 + 28 = 108 4 x 27 = 108
To solve this problem, you would start by dividing 108 by 4, since the problem says that the product of the 4 and another number equals 108. By dividing 108 by 4, you get 27 as the second number. Now, you want the sum of the two numbers, so you add 4 and 27. The sum is 31.
4 x 20 = 80 4 x 7 = 28 80 + 28 = 108 4 x 27 = 108
324*4 = (3*108)*4 = 3*(108*4) So, if you knew 108*4 you could multiply that number by 3 to get the answer to 324*4. But is it not at all clear why you would do that! First of all you need to work out the fact that 324 is actually 108*3 and then, multiplying 324 by 4 is really just as easy or difficult as multiplying 432 by 3. So one more step for no real gain.
105
The LCM of 108 and 22 is 1188. You can't get a "product" of one number.
4 divided by 108 is 0.037
For any two counting numbers x and y:LCM(x, y) x HCF(x, y) = Product of x and yLCM(x, y) = (Product of x and y)/HCF(x, y)Here, we have 108 and 135 & their product = 108 x 135But, HCF(108, 135) = ?So, we shall first calculate HCF by the method of prime factorization.108 = 33x22 & 135 = 33x51It is clear that 33 is the HCF of 108 and 135.So, LCM(108, 135) = (108 x 135)/33 = 4 x 135 = 540