xy = 112 x/y = 7 x = 7y 7y^2 = 112 y^2 = 112/7 = 16 y = 4 x = 28
7 / 8 x 4 / 14 7 x 4 = 28 8 x 14 = 112 28 / 112 same as 1 / 4
4 times the square root of 7
4 times the square root of 7.
Well 800 is divisible by 8 (100), and so is 96 (12), so we can say 896 = 800 + 96 = 8 x 100 + 8 x 12 = 8 x 112. You can divide 112 by 4: 112 / 4 = 28. And 28 = 4 x 7. So we have 896 = 8 x 4 x 4 x 7 = (2^3) x (2^2) x (2^2) x 7 = (2^7) x 7.
56 times 2 = 112 28 times 4 = 112 14 times 8 = 112 7 times 16 = 112
The exponential form of 112 is 2^4 x 7. This is because 112 can be broken down into its prime factors, which are 2 and 7. The exponent of 2 is 4, as 2 is multiplied by itself 4 times to get 16, and 16 is then multiplied by 7 to equal 112. Therefore, the exponential form of 112 is 2^4 x 7.
The square root of 112 simplified is β112 = 4β7. Here's how you can break it down: First, find the prime factorization of 112: 112 = 2^4 * 7. Take the square root of each of the factors: β(2^4 * 7) = β(2^4) * β7 = 2^2 * β7 = 4β7. So, the simplified radical form of β112 is 4β7.
112 = 1 x 112, 2 x 56, 4 x 28, 7 x 16, 8 x 14, 14 x 8, 16 x 7, 28 x 4, 56 x 2, 112 x 1.
4 times.
They are: 2*2*2*2*7 = 112
7 times 16 = 112
8√7. Since the square root of 4 is 2 you just keep dividing the number by 4 and multiplying 2 outside the radical until you get to a number not divisible by 4. (√448 = √[112*4] = 2√112) then (2√112 = 2√[28*4] = 4√28) then (4√28 = 2√[7*4] = 8√7)
Well, darling, if you want to solve for that, just divide 112 by 7, and you'll get your answer. Simple math, my dear. Seven times what equals 112? That would be 16. But hey, who's counting?
xy = 112 x/y = 7 x = 7y 7y^2 = 112 y^2 = 112/7 = 16 y = 4 x = 28
7*2^4
1 x 112, 2 x 56, 4 x 28, 7 x 16, 8 x 14, 14 x 8, 16 x 7, 28 x 4, 56 x 2, 112 x 1 = 112