No. You need one more two. 4 x 2 x 2 x 7 = 112
xy = 112 x/y = 7 x = 7y 7y^2 = 112 y^2 = 112/7 = 16 y = 4 x = 28
7 / 8 x 4 / 14 7 x 4 = 28 8 x 14 = 112 28 / 112 same as 1 / 4
4 times the square root of 7
4 times the square root of 7.
The expression "4 route 7 squared surd" typically refers to ( 4\sqrt{7} ), where "route" indicates the square root and "surd" refers to an irrational number that cannot be simplified further. Squaring this expression would yield ( (4\sqrt{7})^2 = 16 \times 7 = 112 ). Thus, the squared result of ( 4\sqrt{7} ) is 112.
56 times 2 = 112 28 times 4 = 112 14 times 8 = 112 7 times 16 = 112
The exponential form of 112 is 2^4 x 7. This is because 112 can be broken down into its prime factors, which are 2 and 7. The exponent of 2 is 4, as 2 is multiplied by itself 4 times to get 16, and 16 is then multiplied by 7 to equal 112. Therefore, the exponential form of 112 is 2^4 x 7.
The square root of 112 simplified is √112 = 4√7. Here's how you can break it down: First, find the prime factorization of 112: 112 = 2^4 * 7. Take the square root of each of the factors: √(2^4 * 7) = √(2^4) * √7 = 2^2 * √7 = 4√7. So, the simplified radical form of √112 is 4√7.
112 = 1 x 112, 2 x 56, 4 x 28, 7 x 16, 8 x 14, 14 x 8, 16 x 7, 28 x 4, 56 x 2, 112 x 1.
4 times.
They are: 2*2*2*2*7 = 112
7 times 16 = 112
8√7. Since the square root of 4 is 2 you just keep dividing the number by 4 and multiplying 2 outside the radical until you get to a number not divisible by 4. (√448 = √[112*4] = 2√112) then (2√112 = 2√[28*4] = 4√28) then (4√28 = 2√[7*4] = 8√7)
7*2^4
xy = 112 x/y = 7 x = 7y 7y^2 = 112 y^2 = 112/7 = 16 y = 4 x = 28
1 x 112, 2 x 56, 4 x 28, 7 x 16, 8 x 14, 14 x 8, 16 x 7, 28 x 4, 56 x 2, 112 x 1 = 112
The factors of 112 are: 1 2 4 7 8 14 16 28 56 112The prime factors are: 2 7