No. You need one more two. 4 x 2 x 2 x 7 = 112
The number 112 can be divided by several integers, including 1, 2, 4, 7, 8, 14, 16, 28, 56, and 112 itself, which are its divisors. It can also be expressed as a product of its prime factors: (112 = 2^4 \times 7). Additionally, 112 can be used in various mathematical contexts, such as being a part of multiples or ratios.
xy = 112 x/y = 7 x = 7y 7y^2 = 112 y^2 = 112/7 = 16 y = 4 x = 28
7 / 8 x 4 / 14 7 x 4 = 28 8 x 14 = 112 28 / 112 same as 1 / 4
4 times the square root of 7
4 times the square root of 7.
56 times 2 = 112 28 times 4 = 112 14 times 8 = 112 7 times 16 = 112
The exponential form of 112 is 2^4 x 7. This is because 112 can be broken down into its prime factors, which are 2 and 7. The exponent of 2 is 4, as 2 is multiplied by itself 4 times to get 16, and 16 is then multiplied by 7 to equal 112. Therefore, the exponential form of 112 is 2^4 x 7.
The square root of 112 simplified is √112 = 4√7. Here's how you can break it down: First, find the prime factorization of 112: 112 = 2^4 * 7. Take the square root of each of the factors: √(2^4 * 7) = √(2^4) * √7 = 2^2 * √7 = 4√7. So, the simplified radical form of √112 is 4√7.
112 = 1 x 112, 2 x 56, 4 x 28, 7 x 16, 8 x 14, 14 x 8, 16 x 7, 28 x 4, 56 x 2, 112 x 1.
4 times.
They are: 2*2*2*2*7 = 112
7 times 16 = 112
8√7. Since the square root of 4 is 2 you just keep dividing the number by 4 and multiplying 2 outside the radical until you get to a number not divisible by 4. (√448 = √[112*4] = 2√112) then (2√112 = 2√[28*4] = 4√28) then (4√28 = 2√[7*4] = 8√7)
xy = 112 x/y = 7 x = 7y 7y^2 = 112 y^2 = 112/7 = 16 y = 4 x = 28
7*2^4
1 x 112, 2 x 56, 4 x 28, 7 x 16, 8 x 14, 14 x 8, 16 x 7, 28 x 4, 56 x 2, 112 x 1 = 112
The factors of 112 are: 1 2 4 7 8 14 16 28 56 112The prime factors are: 2 7