Q: Is 11 divisible by 8 and 3?

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If the sum of the digits in the odd positions starting from the ones digit less the sum of the digits in the even positions (starting with the 10s digit) is divisible by 11, then so is the original number. for 8003: odd position digits: 3 + 0 = 3 even position digits: 0 + 8 = 8 3 - 8 = -5 which is not divisible by 11, so 8003 is NOT divisible by 11.

The smallest number that is divisible by 2 3 4 5 6 8 9 10 11 and 12 is 3,960.

Yes! 552 is divisible by 3 and 8

939 is evenly divisible by 3 939 is divisible by 8, but not evenly, quotient is 117, remainder is 3

Yes. It equals 45. A quick rule for numbers to see if they are divisible by 3 is to add all the numbers, for example: 207 = 2 + 0 + 7 = 9 Is 9 divisible by 3...Yes! It helps reduce the large numbers, for an easier answer. The number 8649... 8 + 6 + 4 + 9 = 27 and 27 is divisible by 3, so 8649 is also divisible by 3. BUT...137: 1 + 3 + 7 = 11 11 is not divisible by 3...so, 137 is not divisible by 3.

Related questions

8 of the numbers less than 660 are divisible by 5 and 11 but not 3. All numbers divisible by 5 and 11 are multiples of their lcm; lcm(5, 11) = 55 All numbers divisibile by 5, 11 and 3 are multiples of their lcm; lcm(5, 11, 3) = 165 659 ÷ 55 = 11 54/55 → 11 numbers less than 660 are divisible by 5 and 11 659 ÷ 165 = 3 164/165 → 3 numbers less than 660 are divisible by 5, 11 and 3 → of the 11 numbers less than 660 divisible by 5 and 11, 3 are also divisible by 3 → 11 - 3 = 8 numbers less than 660 are divisible by 5 and 11 but not 3,.

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If the sum of the digits in the odd positions starting from the ones digit less the sum of the digits in the even positions (starting with the 10s digit) is divisible by 11, then so is the original number. for 8003: odd position digits: 3 + 0 = 3 even position digits: 0 + 8 = 8 3 - 8 = -5 which is not divisible by 11, so 8003 is NOT divisible by 11.

The smallest number that is divisible by 2 3 4 5 6 8 9 10 11 and 12 is 3,960.

Yes! 552 is divisible by 3 and 8

If the last 3 digits are divisible by 8, the number is divisible by 8.

No number less than 648, including those between 2 and 11, is divisible by 648. But 648 is divisible by 2, 3, 4, 6, 8, and 9.

No. 1+9+6=16, which is not divisible by 3; 1+4+6=11, which isn't divisible by 3 either. No. 1+9+6=16, which is not divisible by 3; 1+4+6=11, which isn't divisible by 3 either.

939 is evenly divisible by 3 939 is divisible by 8, but not evenly, quotient is 117, remainder is 3

Yes. It equals 45. A quick rule for numbers to see if they are divisible by 3 is to add all the numbers, for example: 207 = 2 + 0 + 7 = 9 Is 9 divisible by 3...Yes! It helps reduce the large numbers, for an easier answer. The number 8649... 8 + 6 + 4 + 9 = 27 and 27 is divisible by 3, so 8649 is also divisible by 3. BUT...137: 1 + 3 + 7 = 11 11 is not divisible by 3...so, 137 is not divisible by 3.

Sol: 24 = 3 x 8, where 3 and 8 are co-primes. The sum of the digits in the given number is 36, which is divisible by 3. So, the given number is divisible by 3. The number formed by the last 3 digits of the given number is 744, which is divisible by 8. So, the given number is divisible by 8. Thus, the given number is divisible by both 3 and 8, where 3 and 8 are co-primes. So, it is divisible by 3 x 8, i.e., 24.

4828 is divisible by 2 and 4 only.