655/5 = 131
1, 3, 9, 17, 51, 131, 153, 393, 1179, 2227, 6681, 20043
No, 91 is Not a multiple of 3.An easy way to determine if a number is a multiple or divisible by 3 is to add up all itsdigits and see if the sum is divisible by three.For example: 321 , 3 + 2 + 1, Therefore 321 is divisible by 3 or a multiple of 3.Unlike the number 131, 1 + 3 + 1, whose digits sum up to 5, which isn't divisible by 3.So therefore, 91 is 9+1 Therefore 91 is not a multiple of 3.Hope we helped!
3,537 = 3 * 3 * 3 * 131 or 33 * 131
No, not necessarily. 121 is a palindrome number with 3 digits (odd) and is divisible by 11. So this satisfies the premise, but 101, 111, 131, etc are not divisible by 11.An example which satisfies the premise does not prove it true, but one which contradicts the premise is enough to prove it false.
No
No. 117,638 is divisible by: 1, 2, 131, 262, 449, 898, 58819, 117638.
655 is evenly divisible by 1, 5, 131 and 655.
131 is a prime number. It is only evenly divisible by itself and one.
1, 7, 131, 917.
1, 2, 3, 4, 6, 12, 131, 262, 393, 524, 786, 1572
Apart from itself and 1, the number 3013 is divisible by 23 and 131.
655/5 = 131
1, 3, 9, 17, 51, 131, 153, 393, 1179, 2227, 6681, 20043
1, 3, 9, 17, 51, 131, 153, 393, 1179, 2227, 6681, 20043
No, 91 is Not a multiple of 3.An easy way to determine if a number is a multiple or divisible by 3 is to add up all itsdigits and see if the sum is divisible by three.For example: 321 , 3 + 2 + 1, Therefore 321 is divisible by 3 or a multiple of 3.Unlike the number 131, 1 + 3 + 1, whose digits sum up to 5, which isn't divisible by 3.So therefore, 91 is 9+1 Therefore 91 is not a multiple of 3.Hope we helped!
A prime number is a number that is divisible only by 1 and itself; it has no other factors. A composite number is a number that is divisible by more than 2 numbers. The only factors of 131 are 1 and itself. Therefore, 131 is a prime number.