No.
No. 52 is only divisible by: 1, 2, 4, 13, 26, 52.
13 is prime. It is divisible by 1 and 13.
To find the smallest natural number that is a multiple of 13 and divisible by both 4 and 6, we first determine the least common multiple (LCM) of 4 and 6, which is 12. Next, we need to find the smallest multiple of 13 that is also a multiple of 12. The smallest multiple of 13 is 13 itself, but 13 is not divisible by 12. The smallest multiple of 13 that is also divisible by 12 is 156, as ( 156 = 13 \times 12 ). Therefore, the answer is 156.
13 and all its multiples are divisible by 13.
It is 52 because 52/13 = 4
52 is divisible by its factors which are: 1, 2, 4, 13, 26 & 52
52 is the only one of the four divisible by 13. 52 = 4 x 13
Yes. 52 is divisible by: 1, 2, 4, 13, 26 and 52.
There's a trick you can use: A number is divisible by 3 if and only if the sum of its digits is divisible by 3. Here 2+4+5+2 = 13. Is 13 divisible by 3? You decide.
No. 52 is only divisible by: 1, 2, 4, 13, 26, 52.
13 is prime. It is divisible by 1 and 13.
To find the smallest natural number that is a multiple of 13 and divisible by both 4 and 6, we first determine the least common multiple (LCM) of 4 and 6, which is 12. Next, we need to find the smallest multiple of 13 that is also a multiple of 12. The smallest multiple of 13 is 13 itself, but 13 is not divisible by 12. The smallest multiple of 13 that is also divisible by 12 is 156, as ( 156 = 13 \times 12 ). Therefore, the answer is 156.
13 and all its multiples are divisible by 13.
306 is not divisible by 13.
1,586 is divisible by: 1 2 13 26 61 122 793 1586.
It is 52 because 52/13 = 4
A number is divisible by 13 if it is a multiple of 13. In other words, 13 times a number results in a big number that is divisible by 13.