2, 7, and 14.
Yes they are. They are both divisible by 7. 14/2= 7 and 63/9=7
28 is divisible by: 1, 2, 4, 7, 14, 28.
182 is divisible by: 1, 2, 7, 13, 14, 26, 91, 182.
The number must be divisible by 2 and by 7.
2, 7, and 14.
They are both divisible by: 14, 7, 2 and 1
Yes they are. They are both divisible by 7. 14/2= 7 and 63/9=7
14
1, 2, 7, 14 1, 2, 11, 22
No, 7 is a natural number divisible by 7 and not 14 for example. In fact every odd multiple of 7 (i.e. 7 times 1,3,5,7,...) is divisible by 7 and not 14.
Any multiple of 14.
no 7 is divisible by 14. :)
28 is divisible by: 1, 2, 4, 7, 14, 28.
28 is divisible by 1, 2, 4, 7, 14, 28.
You can determine if a number is divisible by 7 by using the following method: E.g. 161 - Double the last digit (2 x 1 = 2) Subtract 2 from the number formed by the the remaining digits in this case, 16 -2 = 14 If the result is divisible by 7 (14 /7 =2); then the original number is divisible by 7. 161 / 7 = 23
no, it is divisible by 1, 2, 5, 7, 10, 14, 35, 70