No. There are no integers that when multiplied by themselves equal 17.
1 is a perfect square.
289
the square root of 17 is not a perfect square, so it can't be reduced to a rational number. √17 ≈ 4.1231 but the decimal place keeps going on forever
* Its square root is a whole #. Example: 16 is a perfect square. Its square root is 4. 17 is not a perfect square. Its square root is around 4.123105626
No. There are no integers that when multiplied by themselves equal 17.
1 is a perfect square.
289 is a perfect squarebecause 289 = 17*17
yes, 17*17=289, square root of 289 is 17
289 is a perfect squarebecause 289 = 17 x 17
289
the square root of 17 is not a perfect square, so it can't be reduced to a rational number. √17 ≈ 4.1231 but the decimal place keeps going on forever
* Its square root is a whole #. Example: 16 is a perfect square. Its square root is 4. 17 is not a perfect square. Its square root is around 4.123105626
17 of them. 17 of them. 17 of them. 17 of them.
17 is a prime number. Its only factors are 1 and 7. Since 1 is a perfect square, it is the answer to the question.
There are two: 25 and 36.
16 and 25 42 and 52