No, but it is divisible by 1, 3, 17, 51.
No, and here is why: If you want to find out of a number is divisible by 3, you add up the numerals in the number, and see if that total is divisible by 3. In this case, we find that 2+6+9+0 equals 17. 17 is not divisible by 3, therefore, 2690 is not divisible by 3 either.
39 is divisible by 3. It equals 13. You can tell if a number is divisible by 3 by adding up the digits in the number and see if it is divisible by three. Here's and example: 197 1+9+7= 17 and 17 isn't divisible by three. 576 5+7+6= 18 and 3 goes into 18 6 times so it is divisible by 3
there are 17 divisible by 3 between 50 to 100 , 51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
68 is divisible by 17 but not by 3.
No, but it is divisible by 1, 3, 17, 51.
No, and here is why: If you want to find out of a number is divisible by 3, you add up the numerals in the number, and see if that total is divisible by 3. In this case, we find that 2+6+9+0 equals 17. 17 is not divisible by 3, therefore, 2690 is not divisible by 3 either.
Yes, It is 17
156/9 = 17 with a remainder of 3 or 17 and 3/9 or 17 and 1/3 or 17.333333
5 + 1 = 6 which is divisible by 3, so 51 is divisible by 3. [3 x 17 = 51]
1, 3, 17, 51
39 is divisible by 3. It equals 13. You can tell if a number is divisible by 3 by adding up the digits in the number and see if it is divisible by three. Here's and example: 197 1+9+7= 17 and 17 isn't divisible by three. 576 5+7+6= 18 and 3 goes into 18 6 times so it is divisible by 3
there are 17 divisible by 3 between 50 to 100 , 51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99
No, it is not. 51 is divisible by 3 and 17
3 x17 is 51 51 is not a prime number it is composite. use this rule : You wil know a number is divisible by 3 if you add up the digits. if the sum is a multiple of 3 then that number is divisible by 3. i.e.: 51 5+1 =6 6 is divisible by 3 so 51 is divisible by 3. 51/3= 17
No, 153 is only divisible by: 1, 3, 9, 17, 51, 153.