No, but it is divisible by 1, 3, 17, 51.
No, and here is why: If you want to find out of a number is divisible by 3, you add up the numerals in the number, and see if that total is divisible by 3. In this case, we find that 2+6+9+0 equals 17. 17 is not divisible by 3, therefore, 2690 is not divisible by 3 either.
39 is divisible by 3. It equals 13. You can tell if a number is divisible by 3 by adding up the digits in the number and see if it is divisible by three. Here's and example: 197 1+9+7= 17 and 17 isn't divisible by three. 576 5+7+6= 18 and 3 goes into 18 6 times so it is divisible by 3
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
102 For a number to be divisible by 6, it must be divisible by both 2 and 3. 102 div by 2 = 51; 102 div by 3 = 17
68 is divisible by 17 but not by 3.
No, but it is divisible by 1, 3, 17, 51.
No, and here is why: If you want to find out of a number is divisible by 3, you add up the numerals in the number, and see if that total is divisible by 3. In this case, we find that 2+6+9+0 equals 17. 17 is not divisible by 3, therefore, 2690 is not divisible by 3 either.
Yes, It is 17
156/9 = 17 with a remainder of 3 or 17 and 3/9 or 17 and 1/3 or 17.333333
5 + 1 = 6 which is divisible by 3, so 51 is divisible by 3. [3 x 17 = 51]
1, 3, 17, 51
39 is divisible by 3. It equals 13. You can tell if a number is divisible by 3 by adding up the digits in the number and see if it is divisible by three. Here's and example: 197 1+9+7= 17 and 17 isn't divisible by three. 576 5+7+6= 18 and 3 goes into 18 6 times so it is divisible by 3
3 x17 is 51 51 is not a prime number it is composite. use this rule : You wil know a number is divisible by 3 if you add up the digits. if the sum is a multiple of 3 then that number is divisible by 3. i.e.: 51 5+1 =6 6 is divisible by 3 so 51 is divisible by 3. 51/3= 17
No, it is not. 51 is divisible by 3 and 17
No, 153 is only divisible by: 1, 3, 9, 17, 51, 153.
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.