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What else can I help you with?
How do you solve 7x plus 51x plus 14?
7x + 51x + 14= 58x + 14= 2(29x + 7)
What is 21x cubed-58x plus 21?
It's a third-degree polynomial in 'x'. It's value depends on the value of 'x'. Every time 'x' changes, the value of the polynomial changes.
-58x - 26 8x - 230.6?
My best guess is that you have an exercise which is headed (and thus gives the context): "solve for x in the following equations", though it could quite easily be: solve for x in the following inequalities".As such, there is some sign between the 26 and 8x which unfortunately has been stripped out; it is one of {=≤≥}If I solve it for equals (=), then the others will follow:-58x - 26 = 8x - 230.6→ -26 + 230.6 = 58x + 8x→ 204.6 = 64x→ 3.196875 = xI have deliberately left the x on the right so that when the inequalities are inserted, the correct answer is given:-58x - 26 = 8x - 230.6 → 3.196875 = x, or with x on the left: x = 3.196875-58x - 26 < 8x - 230.6 → 3.196875 < x, or with x on the left: x > 3.196875-58x - 26 > 8x - 230.6 → 3.196875 > x, or with x on the left: x < 3.196875-58x - 26 ≤ 8x - 230.6 → 3.196875 ≤ x, or with x on the left: x ≥ 3.196875-58x - 26 ≥ 8x - 230.6 → 3.196875 ≥ x, or with x on the left: x ≤ 3.196875Note the change of the inequalities when the x is shifted from the right to the left so that the same meaning is read.
How do you simplify 10x(x-1)-8(6x plus 2)?
To simplify the expression (10x(x-1) - 8(6x + 2)), first distribute the terms: (10x(x - 1) = 10x^2 - 10x) (-8(6x + 2) = -48x - 16) Now, combine the results: (10x^2 - 10x - 48x - 16 = 10x^2 - 58x - 16). Thus, the simplified expression is (10x^2 - 58x - 16).
What are the possible values of x and y when d equals 58x plus 145y and that d is the HCF of 58 and 145 showing work?
If d is the highest common factor of 58 and 145 then d equals 29:- So: 29 = 58x+145y Divide all terms by 29: 1 = 2x+5y Or: 2*1/4+5*1/10 = 1 Therefore the possible values of x and y are 1/4 and 1/10 respectively Check: 58*1/4 plus 145*1/10 = 29
What is 7x plus 58x plus 8?
56x^2 + 96x + 40
15x2 plus 58x plus 48?
15x2 + 58x + 48= 15x2 + 18x + 40x + 48= 3x(5x + 6) + 8(5x + 6)= (3x + 8)(5x + 6)
How do you solve 7x plus 51x plus 14?
7x + 51x + 14= 58x + 14= 2(29x + 7)
How do you factor this trinomial 40x2-58x plus 12?
2(4x - 1)(5x - 6)
6x squared minus 58x plus 80 equals 0?
6x2 + 58x + 80 = 02(40 + 29x + 3x2) = 02((8 + x)(5 + 3x)) = 0, ignore 28 + x = 0 => x = -85 + 3x = 0 => 3x = 5 => x= 1.666666....x = {-8, 1.66....}
What is 21x cubed-58x plus 21?
It's a third-degree polynomial in 'x'. It's value depends on the value of 'x'. Every time 'x' changes, the value of the polynomial changes.
58 percent of what is 63.4?
.58x = 63.4 x = 63.4/.58 x = 109.31
-58x - 26 8x - 230.6?
My best guess is that you have an exercise which is headed (and thus gives the context): "solve for x in the following equations", though it could quite easily be: solve for x in the following inequalities".As such, there is some sign between the 26 and 8x which unfortunately has been stripped out; it is one of {=≤≥}If I solve it for equals (=), then the others will follow:-58x - 26 = 8x - 230.6→ -26 + 230.6 = 58x + 8x→ 204.6 = 64x→ 3.196875 = xI have deliberately left the x on the right so that when the inequalities are inserted, the correct answer is given:-58x - 26 = 8x - 230.6 → 3.196875 = x, or with x on the left: x = 3.196875-58x - 26 < 8x - 230.6 → 3.196875 < x, or with x on the left: x > 3.196875-58x - 26 > 8x - 230.6 → 3.196875 > x, or with x on the left: x < 3.196875-58x - 26 ≤ 8x - 230.6 → 3.196875 ≤ x, or with x on the left: x ≥ 3.196875-58x - 26 ≥ 8x - 230.6 → 3.196875 ≥ x, or with x on the left: x ≤ 3.196875Note the change of the inequalities when the x is shifted from the right to the left so that the same meaning is read.
How do you simplify 10x(x-1)-8(6x plus 2)?
To simplify the expression (10x(x-1) - 8(6x + 2)), first distribute the terms: (10x(x - 1) = 10x^2 - 10x) (-8(6x + 2) = -48x - 16) Now, combine the results: (10x^2 - 10x - 48x - 16 = 10x^2 - 58x - 16). Thus, the simplified expression is (10x^2 - 58x - 16).
What are the possible values of x and y when d equals 58x plus 145y and that d is the HCF of 58 and 145 showing work?
If d is the highest common factor of 58 and 145 then d equals 29:- So: 29 = 58x+145y Divide all terms by 29: 1 = 2x+5y Or: 2*1/4+5*1/10 = 1 Therefore the possible values of x and y are 1/4 and 1/10 respectively Check: 58*1/4 plus 145*1/10 = 29
If you have 58 people and 54 are trained what is the percent?
is/of=%/10054/58=%/10058X%=5400x%=5400/58x%=93.103448 or about 93 percent
What is the sum of two consecutive integers is 59 and put it in an equation?
Algebraically. X = integers.X + (X + 1) = 592X + 1 = 592X = 58X = 29X + 1 = 30(29, 30)=======
