Any of its multiples
No. 1,827 is only divisible by 1, 3, 7, 9, 21, 29, 63, 87, 203, 261, 609, 1827.
If a number is divisible by 2 and 3, it is divisible by 6.
To determine if 483 is divisible by 6, we need to check if 483 divided by 6 results in a whole number. When we divide 483 by 6, we get 80 with a remainder of 3. Since there is a remainder, 483 is not divisible by 6.
238 is not divisible by 6. It is not also divisible by 3. However, it is divisible by 2.
No, because when something is divisible by 6, it is divisible by 2 or 3. This is divisible by 3, but not 2.
3 9 0
Any of its multiples
1,827 is divisible by: 1, 3, 7, 9, 21, 29, 63, 87, 203, 261, 609, 1827.
No. 1,827 is only divisible by 1, 3, 7, 9, 21, 29, 63, 87, 203, 261, 609, 1827.
Because the final digital sum is 9 then it is divisible by 9 as follows 1827/9 = 203
Any of its factors: 1, 3, 7, 9, 21, 29, 63, 87, 203, 261, 609, 1827
6 is not divisible by 162. 162 is divisible by 6.
If it is divisible by 2 and 3, it is divisible by 6.
if a number is divisible by 2 and 3 then its divisible by 6
If a number is divisible by 2 and 3, it is divisible by 6.
No odd number can be evenly divisible by 6. Since 6 is divisible by 2, any number that is divisible by 6 will automatically be divisible by 2.