To find out if 1859 is a prime number, use the rules of division:1859 is not an even number, so it is not divisible by 2.The digits of 1859 add up to a number that is divisible by 3, so it is not divisible by 3.The last two digits (59) is not divisible by 4, so neither is 1859.The last digit is not 5, so it is not divisible by 5.1859 is not divisible by 2 and it is not divisible by 3, so it is not divisible by 6.When you double the last digit (9 doubled is 18), and subtract that number from the rest of the number (859 - 18 = 841), if the answer is 0 or divisible by 7, the number itself is divisible by 7. If you can't readily tell if the number is divisible by 7, you can do the steps again. Starting with 841, doubling the 1 is still 1, so take 1 away from 84 to get 83. 83 is not divisible by 7, so neither is 1859.The last three digits (859) are not divisible by 8, so 1859 is not divisible by 8.If the sum of the digits is divisible by 9, the number is divisible by 9. The sum of the digits is 23, which is not divisible by 9.1859 does not end with a 0, so it is not divisible by 10.If the sum of every second digit (8 + 9) minus the sum of the other digits (1 + 5) equals 0 or is divisible by 11, the number itself is divisible by 11. 17 - 6 = 11, so 1859 is divisible by 11.Since 1859 is divisible by 11, it is a composite number (a number that has at least three factors: 1, the number itself, and at least one oher factor).
The factors of 1859 are: 1, 11, 13, 143, 169, 1859.
If a number is divisible by 2 and 3, it is divisible by 6.
To determine if 483 is divisible by 6, we need to check if 483 divided by 6 results in a whole number. When we divide 483 by 6, we get 80 with a remainder of 3. Since there is a remainder, 483 is not divisible by 6.
238 is not divisible by 6. It is not also divisible by 3. However, it is divisible by 2.
No, it is not evenly divisible.
To find out if 1859 is a prime number, use the rules of division:1859 is not an even number, so it is not divisible by 2.The digits of 1859 add up to a number that is divisible by 3, so it is not divisible by 3.The last two digits (59) is not divisible by 4, so neither is 1859.The last digit is not 5, so it is not divisible by 5.1859 is not divisible by 2 and it is not divisible by 3, so it is not divisible by 6.When you double the last digit (9 doubled is 18), and subtract that number from the rest of the number (859 - 18 = 841), if the answer is 0 or divisible by 7, the number itself is divisible by 7. If you can't readily tell if the number is divisible by 7, you can do the steps again. Starting with 841, doubling the 1 is still 1, so take 1 away from 84 to get 83. 83 is not divisible by 7, so neither is 1859.The last three digits (859) are not divisible by 8, so 1859 is not divisible by 8.If the sum of the digits is divisible by 9, the number is divisible by 9. The sum of the digits is 23, which is not divisible by 9.1859 does not end with a 0, so it is not divisible by 10.If the sum of every second digit (8 + 9) minus the sum of the other digits (1 + 5) equals 0 or is divisible by 11, the number itself is divisible by 11. 17 - 6 = 11, so 1859 is divisible by 11.Since 1859 is divisible by 11, it is a composite number (a number that has at least three factors: 1, the number itself, and at least one oher factor).
The factors of 1859 are: 1, 11, 13, 143, 169, 1859.
6 is not divisible by 162. 162 is divisible by 6.
If it is divisible by 2 and 3, it is divisible by 6.
if a number is divisible by 2 and 3 then its divisible by 6
If a number is divisible by 2 and 3, it is divisible by 6.
No odd number can be evenly divisible by 6. Since 6 is divisible by 2, any number that is divisible by 6 will automatically be divisible by 2.
Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.
To determine if 483 is divisible by 6, we need to check if 483 divided by 6 results in a whole number. When we divide 483 by 6, we get 80 with a remainder of 3. Since there is a remainder, 483 is not divisible by 6.
138 is divisible by 6. Any number is divisible by 6 if it is an even number that also is divisible by 3.
If this is a T-F question, the answer is false. It is true that if a number is divisible by 6, it also divisible by 3. This is true because 6 is divisible by 3. However, the converse -- If a number is divisible by 3, it is divisible by 6, is false. A counterexample is 15. 15 is divisible by 3, but not by 6. It becomes clearer if you split the question into its two parts. A number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. A number is divisible by 6 only if it is divisible by 3? True.