No, 8 is not a factor of 18, but 1, 2, 3, 6, and 9 are factors of 18.
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No, but it is divisible by 9 and 2
The sum of the factors are divisible by 9. Ex: 738 7+3+8=18 18/9=2
138 is not divisible by 18.
8/9 They are both divisible by 2
Any number whose digits add up to a multiple of three. Example: 189 is divisible by 3 because 1+8+9=18 and 18 is divisible by 3.