The probability of getting a 2 is (1/6) as there are 6 sides, the probability of then getting an even number 2,4, or 6 is 3/6 or (1/2). Therefore those 2 even occurring together are 1/6 X 1/2 =1/12 or 8.5%.
No. For example, the factors of 6 are 1, 2, 3, and 6. Two of these are even, the others are odd.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 6 is an even number.
0/6 + 1/6 + 0/6 + 1/6 + 0/6 + 1/6 = 3/6 = 1/2 = 50%
No number can satisfy these conditions: To have a remainder of 1 when divided by 6, the number must be odd (as all multiples of 6 are even and an even number plus 1 is odd) To have a remainder of 2 when divided by 8, the number must be even (as all multiples of 8 are even and an even number plus 2 is even) No number is both odd and even. → No number exists that has a remainder of 1 when divided by 6, and 2 when divided by 8.
The probability of getting a 2 is (1/6) as there are 6 sides, the probability of then getting an even number 2,4, or 6 is 3/6 or (1/2). Therefore those 2 even occurring together are 1/6 X 1/2 =1/12 or 8.5%.
50%, 1/2 or 3/6. 1, 3 and 5 are odd, and 2, 4 and 6 are even.
Think about it; there is a 1 of 6 chance it lands on a particular number, like 4. there are 3 even numbers; 2,4,6. 1/6 chance for 2, 1/6 chance for 4, 1/6 chance for 6. 1/6+1/6+1/6=3/6 or 1/2. solve from there.
There are 6 numbers on the die; 3 even. Therefore P(Even) = 3/6 or 1/2.
There are 6 numbers on the die; 3 even. Therefore P(Even) = 3/6 or 1/2.
1/6,3/6 ----------------------------------------------------------------------------------------------------- The probability of rolling a 2 is: P(2) = 1/6 The probability of rolling an even number is: P(even) = 1/2 The result on the second roll is independent of the result in the first roll. The probability of rolling a 2 and then rolling an even number is: P(2,even no.) = (1/6) ∙ (1/2) = 1/12 = 0.08333... ≈ 8.33%
No. For example, the factors of 6 are 1, 2, 3, and 6. Two of these are even, the others are odd.
P(not even) = P(odd) = 3/6=1/3 When rolled 6 times, the probability of an even number not showing up is (1/3)^6 = 1/729.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 6 is an even number.
0/6 + 1/6 + 0/6 + 1/6 + 0/6 + 1/6 = 3/6 = 1/2 = 50%
Not even 1
No number can satisfy these conditions: To have a remainder of 1 when divided by 6, the number must be odd (as all multiples of 6 are even and an even number plus 1 is odd) To have a remainder of 2 when divided by 8, the number must be even (as all multiples of 8 are even and an even number plus 2 is even) No number is both odd and even. → No number exists that has a remainder of 1 when divided by 6, and 2 when divided by 8.