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The probability of getting a 2 is (1/6) as there are 6 sides, the probability of then getting an even number 2,4, or 6 is 3/6 or (1/2). Therefore those 2 even occurring together are 1/6 X 1/2 =1/12 or 8.5%.
No. For example, the factors of 6 are 1, 2, 3, and 6. Two of these are even, the others are odd.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 6 is an even number.
0/6 + 1/6 + 0/6 + 1/6 + 0/6 + 1/6 = 3/6 = 1/2 = 50%
No number can satisfy these conditions: To have a remainder of 1 when divided by 6, the number must be odd (as all multiples of 6 are even and an even number plus 1 is odd) To have a remainder of 2 when divided by 8, the number must be even (as all multiples of 8 are even and an even number plus 2 is even) No number is both odd and even. → No number exists that has a remainder of 1 when divided by 6, and 2 when divided by 8.