28 millimetres, as stated in the question.
Using Pythagoras: hypotenuse2 = one_leg2 + other_leg2 ⇒ hypotenuse = √(one_leg2 + other_leg2) = √(212 + 282) = √1225 = 35 units.
21^2+28^2=c^2 441+784=c^2 1225=c^2 35=c
Using Pythagoras' theorem it is 35 inches
There are no first 5 multiple. Multiple is singular.
The right-angle triangle measures 28cm by 35cm. Such a triangle is half of a rectangle.Therefore 28 x 35 = 980cm2 is the area of a rectangle.980 / 2 = 490cm2 will give the area of the triangle (which is 490cm2).
28 millimetres, as stated in the question.
Not enough information has been given to work out side A such as any of its angles upon which the sine rule could have been used to find side A but if the given triangle is a right angle triangle then side A is 28 which conforms to Pythagoras theorem for a right angle triangle.
It is: (21+35)/2 = 28
Using Pythagoras: hypotenuse2 = one_leg2 + other_leg2 ⇒ hypotenuse = √(one_leg2 + other_leg2) = √(212 + 282) = √1225 = 35 units.
15: 1,3,5,15 28: 1,2,4,7,14,28 21: 1,3,7,21 35: 1,5,7,35
The Least Common Multiple (LCM) of 35, 21, and 28 is 420.
21^2+28^2=c^2 441+784=c^2 1225=c^2 35=c
The LCM of 2135 and 28 is 8540 The LCM of 21, 35 and 28 is 420.
7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84.
35
The Least Common Multiple (LCM) for 28 35 21 14 is 420.