Yes
28 millimetres, as stated in the question.
Using Pythagoras: hypotenuse2 = one_leg2 + other_leg2 ⇒ hypotenuse = √(one_leg2 + other_leg2) = √(212 + 282) = √1225 = 35 units.
To find the missing side length of a triangle with sides 21 and 35, we can use the Pythagorean theorem if it's a right triangle. However, if the triangle is not specified as a right triangle, we cannot determine the missing side without additional information, such as the angle between the two sides or whether it is an isosceles triangle. Therefore, more context is needed to calculate the missing side length accurately.
21^2+28^2=c^2 441+784=c^2 1225=c^2 35=c
Using Pythagoras' theorem it is 35 inches
The right-angle triangle measures 28cm by 35cm. Such a triangle is half of a rectangle.Therefore 28 x 35 = 980cm2 is the area of a rectangle.980 / 2 = 490cm2 will give the area of the triangle (which is 490cm2).
28 millimetres, as stated in the question.
It is: (21+35)/2 = 28
Not enough information has been given to work out side A such as any of its angles upon which the sine rule could have been used to find side A but if the given triangle is a right angle triangle then side A is 28 which conforms to Pythagoras theorem for a right angle triangle.
Using Pythagoras: hypotenuse2 = one_leg2 + other_leg2 ⇒ hypotenuse = √(one_leg2 + other_leg2) = √(212 + 282) = √1225 = 35 units.
15: 1,3,5,15 28: 1,2,4,7,14,28 21: 1,3,7,21 35: 1,5,7,35
The Least Common Multiple (LCM) of 35, 21, and 28 is 420.
The LCM of 2135 and 28 is 8540 The LCM of 21, 35 and 28 is 420.
21^2+28^2=c^2 441+784=c^2 1225=c^2 35=c
To find the number halfway between any two numbers x and y, add x and y, then divide the answer by 2. So for 21 and 35, 21+ 35 = 56. 56/2 = 28. You can check your answer by seeing that 21 + 7 = 28 and 35 - 7 = 28.
7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84.
35