28 millimetres, as stated in the question.
Using Pythagoras: hypotenuse2 = one_leg2 + other_leg2 ⇒ hypotenuse = √(one_leg2 + other_leg2) = √(212 + 282) = √1225 = 35 units.
21^2+28^2=c^2 441+784=c^2 1225=c^2 35=c
Using Pythagoras' theorem it is 35 inches
There are no first 5 multiple. Multiple is singular.
The right-angle triangle measures 28cm by 35cm. Such a triangle is half of a rectangle.Therefore 28 x 35 = 980cm2 is the area of a rectangle.980 / 2 = 490cm2 will give the area of the triangle (which is 490cm2).
28 millimetres, as stated in the question.
It is: (21+35)/2 = 28
Not enough information has been given to work out side A such as any of its angles upon which the sine rule could have been used to find side A but if the given triangle is a right angle triangle then side A is 28 which conforms to Pythagoras theorem for a right angle triangle.
Using Pythagoras: hypotenuse2 = one_leg2 + other_leg2 ⇒ hypotenuse = √(one_leg2 + other_leg2) = √(212 + 282) = √1225 = 35 units.
The Least Common Multiple (LCM) of 35, 21, and 28 is 420.
15: 1,3,5,15 28: 1,2,4,7,14,28 21: 1,3,7,21 35: 1,5,7,35
The LCM of 2135 and 28 is 8540 The LCM of 21, 35 and 28 is 420.
21^2+28^2=c^2 441+784=c^2 1225=c^2 35=c
To find the number halfway between any two numbers x and y, add x and y, then divide the answer by 2. So for 21 and 35, 21+ 35 = 56. 56/2 = 28. You can check your answer by seeing that 21 + 7 = 28 and 35 - 7 = 28.
7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84.
35