To create a whole number, no.
Otherwise it would be 2 remainder 3 or 2 1/3
A number is divisible by 9 if the sum of its digits is divisible by 9. For 3,333,333, the sum of the digits is 3 + 3 + 3 + 3 + 3 + 3 + 3 = 21. Since 21 is not divisible by 9 (21 divided by 9 equals 2 with a remainder of 3), 3,333,333 is also not divisible by 9.
To determine if 10534341 is divisible by 9, add the digits (1+0+5+3+4+3+4+1 = 21); since 21 is divisible by 9, the number is divisible by 9. For divisibility by 3, the sum of the digits (21) is also divisible by 3. However, for divisibility by 2, the number must be even, and since 10534341 ends in 1, it is not divisible by 2. Therefore, 10534341 is divisible by 9 and 3, but not by 2.
To check if 10,534,341 is divisible by 3, add the digits: 1 + 0 + 5 + 3 + 4 + 3 + 4 + 1 = 21, which is divisible by 3, so 10,534,341 is divisible by 3. For divisibility by 9, since 21 is not divisible by 9, the number is not divisible by 9. Lastly, since the last digit is 1 (an odd number), it is not divisible by 2. Therefore, 10,534,341 is divisible by 3 only.
no. if you divided it by nine you would get a number with a big decimal. But is divisible by 5. (105/5=21)
no both are divisible by 3
A number is divisible by 9 if the sum of its digits is divisible by 9. For 3,333,333, the sum of the digits is 3 + 3 + 3 + 3 + 3 + 3 + 3 = 21. Since 21 is not divisible by 9 (21 divided by 9 equals 2 with a remainder of 3), 3,333,333 is also not divisible by 9.
To determine if 10534341 is divisible by 9, add the digits (1+0+5+3+4+3+4+1 = 21); since 21 is divisible by 9, the number is divisible by 9. For divisibility by 3, the sum of the digits (21) is also divisible by 3. However, for divisibility by 2, the number must be even, and since 10534341 ends in 1, it is not divisible by 2. Therefore, 10534341 is divisible by 9 and 3, but not by 2.
To check if 10,534,341 is divisible by 3, add the digits: 1 + 0 + 5 + 3 + 4 + 3 + 4 + 1 = 21, which is divisible by 3, so 10,534,341 is divisible by 3. For divisibility by 9, since 21 is not divisible by 9, the number is not divisible by 9. Lastly, since the last digit is 1 (an odd number), it is not divisible by 2. Therefore, 10,534,341 is divisible by 3 only.
no. if you divided it by nine you would get a number with a big decimal. But is divisible by 5. (105/5=21)
no both are divisible by 3
1, 3, 7, 9, 21, 63
To determine if 1965 is divisible by 3, you can add its digits together: 1 + 9 + 6 + 5 = 21. Since 21 is divisible by 3, this means that 1965 is also divisible by 3. Therefore, yes, 1965 is divisible by 3.
3*21 = 63 so 63 is divisible by 3 7*9 = 63 so 63 is divisible by 7.
1, 63, 3, 21, 7, 9
To check divisibility of 9, add the digits together. add the digits again if your answer has 2 or more digits. you should get 9 as the remaining digit to be divisible by 9. 4 + 0 + 8 + 9 = 21 2 + 1 = 3 So 4089 is not divisible by 9.
Nope - To be divisible by nine, the sum of the digits must also be divisible by 9 (the digits total 21). Additionally, since it's an odd number - it cannot be divided by 6 !