No, 255.247.0.0 is not a valid subnet mask. A valid subnet mask must have contiguous bits set to 1 followed by contiguous bits set to 0, which means that after the 1s, all subsequent bits should be 0. The binary representation of 255.247.0.0 does not adhere to this rule, as it has non-contiguous 1s and 0s.
This is not a valid IP address - a valid IP address has 4 bytes. Also, you can't guess the subnet mask from looking only at the IP address; there are usually several options.
Yes, the IP subnet 88.33.0.0 with a mask of 255.255.128.0 overlaps with the subnet 88.33.89.0 with the same mask. The subnet mask 255.255.128.0 indicates that the first 17 bits are the network part, meaning subnets can range from 88.33.0.0 to 88.33.127.255. Since 88.33.89.0 falls within this range, the two subnets indeed overlap.
Subnet Mask: Subnet mask is a 32 bits value which differentiate the host portion & network portion of an IP address. Where network portion is designate by the 1's & host portion 0's. Wild card Mask: Wild card mask defines which IP addresses are allowed & which are blocked. Where 0's defines the accurate match where non zero value defines any value on the corresponding octete.
The default subnet mask for the IP address 191.249.234.191 is 255.255.255.0. This is because the address belongs to Class B, which typically uses a default subnet mask of 255.255.0.0. However, if it's using CIDR notation for subnetting, it may also commonly be configured with a mask of 255.255.255.0 for more specific network segmentation.
To find the broadcast address for the IP address 136.78.113.75 with the subnet mask 255.255.244.0, first convert the subnet mask to binary: 11111111.11111111.11111100.00000000. This means the first 22 bits are for the network. When you apply this mask to the IP address, the network portion is 136.78.112.0. The broadcast address, which has all host bits set to 1, is 136.78.115.255.
This is a network address
No choices were supplied; cannot answer the question.
To Know any subnet of this IP you must provide the Subnet mask, otherwise it is impossible to know what is the subnet.
This is not a valid IP address - a valid IP address has 4 bytes. Also, you can't guess the subnet mask from looking only at the IP address; there are usually several options.
That's not a valid subnet mask. Probably the subnet mask is supposed to be 255.255.192.0. You can convert each of the parts separated by dots to binary separately. Just use a scientific calculator, for example, the one that comes with Windows. To be a valid subnet mask, the binary equivalent must have a certain number of only ones, followed by only zeros.
This isn't a valid CIDR address, so I assume it is: 192.168.1.162/7 That would yield a subnet mask of 255.255.255.254
It does not require a subnet mask.
If this is a default subnet mask, then it would be a class C subnet mask. If you are subnetting a network and this is not the default subnet mask, then it could be either a class A or class B.
The default subnet mask has a standard size. The custom subnet mask allows you to make subnets that are smaller or larger than the default.
255.255.255.0
2 given subnets
255.255.255.0