3 is the remainder when 23 is divided by 10. 2 x 10 = 20, and 23 is 3 more than 20.
No,it is not: 163 divided by 7 is 23 with a remainder of 2. If there is a remainder it is not divisible by that number.
58
10.4
Yes because there is no legit remainder. If you do 4 divided by 2 you get 2 with a 0 remainder or no remainder.
This is an extremely poor question. There are 28 pairs of numbers and, in less than 10 minutes, I could find reasons why 17 pair were different from the other numbers in the set. A bit more time and I am sure I could do the rest. So here they are: 53 and 72: leave a remainder of 15 when divided by 19. 53 and 77: leave a remainder of 5 when divided by 12. 53 and 82: leave a remainder of 24 when divided by 29. 53 and 87: leave a remainder of 2 when divided by 17. 53 and 95: leave a remainder of 11 when divided by 21. 53 and 97: leave a remainder of 9 when divided by 11. 67 and 95: leave a remainder of 11 when divided by 28. 67 and 87: leave a remainder of 7 when divided by 17. 67 and 97: leave a remainder of 7 when divided by 30. 72 and 82: leave a remainder of 0 when divided by 2 (are even). 72 and 87: leave a remainder of 0 when divided by 3 (multiples of 3). 72 and 95: leave a remainder of 3 when divided by 23. 72 and 97: leave a remainder of 22 when divided by 25. 77 and 95: leave a remainder of 5 when divided by 9. 77 and 97: leave a remainder of 17 when divided by 20. 82 and 95: leave a remainder of 4 when divided by 13. 87 and 95: leave a remainder of 7 when divided by 8.
2.4348
0.087
7.6667
23 is an odd number between 10 and 30 that gives a remainder of 2 when divided by 7.
10
57.087
7.6667
11.5
3.2
23.5
0.087
7.6667