This is called an incomplete quadratic equation because there is no linear term. aX2 +( bX)+ c = 0 The middle term is not there, but this is quite solvable.
No, It's a a quadratic equation because you have X squared.
Because when your solving a quadratic equation your looking for x-intercepts which is where why equals 0 and x equals what ever the answer is.
2x^3(x - 3)(x + 3)
No. It is a linear equation (y = 5/2 x + 5). A quadratic equation requires a squared term, for example y = x2 + 5x + 6; this can be solved for x given y = 0, as in solving x2 + 5x + 6 = 0.
This is called an incomplete quadratic equation because there is no linear term. aX2 +( bX)+ c = 0 The middle term is not there, but this is quite solvable.
No, It's a a quadratic equation because you have X squared.
a is the coefficient of the x2 term. If is a = 0, then it is no longer a quadratic - it is just a linear equation, and the quadratic formula will not work to solve it.
Because when your solving a quadratic equation your looking for x-intercepts which is where why equals 0 and x equals what ever the answer is.
2x^3(x - 3)(x + 3)
No
No. It is a linear equation (y = 5/2 x + 5). A quadratic equation requires a squared term, for example y = x2 + 5x + 6; this can be solved for x given y = 0, as in solving x2 + 5x + 6 = 0.
You can easily tell by substituting 0 for a.
It is linear.
When the quadratic is written in the form: y = ax2 + bx + c then if a > 0 y has a minimum if a < 0 y has a maximum and if a = 0 y is not a quadratic but y = bx + c, and it is linear. The maximum or minimum is at x = -b/(2a)
y = 0" the answer is YES.
y=±√15