-5y +2x = -10 -5y = -2x -10 y = 2/5x +2 So the slope = 2/5 and the y intercept = 2
(-5, 2)
If: 2x+5y = -10 Then by subtracting 2x from both sides: 5y = -2x-10 And dividing all terms by 5: y = -2/5x-2 which is now in slope intercept form
2x + 5y = 10Subtract 2x from each side:5y = -2x + 10Divide each side by 5:y = - (2/5)x + 2Slop = - (2/5)Y-intercept = 2
2X - 5Y = 2- 5Y = - 2X + 2Y = (2/5)X - 2/5==================
-5y +2x = -10 -5y = -2x -10 y = 2/5x +2 So the slope = 2/5 and the y intercept = 2
(-5, 2)
2x + 2 is an algebraic expression. It is also a polynomial and it has two terms: 2x and 2.
2x-5y+15=0 -5y=-2x-15 y=(2/5)x+3
If: 2x+5y = -10 Then by subtracting 2x from both sides: 5y = -2x-10 And dividing all terms by 5: y = -2/5x-2 which is now in slope intercept form
2x - 5y = -10 So 5y = 2x + 10 and therefore y = (2/5)*x plus something So the slope is 2/5 or 0.4
2x + 5y = 10Subtract 2x from each side:5y = -2x + 10Divide each side by 5:y = - (2/5)x + 2Slop = - (2/5)Y-intercept = 2
2X - 5Y = 2- 5Y = - 2X + 2Y = (2/5)X - 2/5==================
2x + 5y = 16 -2x - 3y = -14 2y = 2 y = 1 / x = 5.5 (5.5,1) or (5 1/2,1)
2(5x + 3y)(2x + 5y)
-2x = 20 + 5y-2x - 20 = 5y-2/5x - 4 = yX Intercept = (-10,0) or -10Y Intercept = (0,-4) or -4
2x + 5y = 3 put into standard form wher y = mx + b and m = slope 5y + 2x = 3 5y = -2x + 3 y = -2/5x + 3/5 m = slope = -2/5