no, but 33 is
Its divisible by 2, 3, 6, 22, 33, 66 & ..................
33 is a composite number as it can be divisible by 1, 3, 11, 33.
No prime numbers can be equal to 33, as 33 is not a prime number. It is divisible by 3. Prime numbers are only divisible by 1 and themselves, and 33 does not meet this criterion.
A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.
Well, honey, let me break it down for you. Yes, 33 is divisible by 1, 3, 11, and 33. So, if you're looking to divide 33 into some smaller chunks, go ahead and have at it. Just don't come crying to me if you end up with a fraction mess on your hands.
Oh, what a lovely question! Let's see, we can find the numbers divisible by 3 first, which are 33 numbers, and the numbers divisible by 7, which are 14 numbers. But wait, some numbers are divisible by both 3 and 7, so we must be careful not to count them twice. In the end, there are 47 numbers between 1 and 100 that are divisible by 3 or 7. Happy counting!
The numbers that are divisible by 33 are infinite. The first four are: 33, 66, 99, 132 . . .
evenly divisible is 33
33
no
No.
No, it is not.
132 is divisible by 1, 2, 3, 4, 6, 11, 12, 22, 33, 44, 66, 132
2*132 3*88 4*66 6*44 8*33 :)
33 is composite, as it is divisible by 3 and 11.
yes and if you ever want to know if something is divisible by 3 add up the number like 3 plus 3 (33) is 6 and it is divisible by 3. by the way the answer is 11. 11x3=33