if you mean wich numbers are not divisable by 4: 35 416 7235 1856 3720 Then: 35 and 7235 are not divisible by 4.
Yes: 140 / 4 = 35
if the number formed by the last two digits is divisible by 4, then the whole number will be divisible by 4 for example, 932 is divisible by 4 because 32 is divisible by 4 19935 is not divisible by 4 because 35 is not divisible by 4 (note: if the last two digits are 00, the number is divisible by 4)
35 is divisible by 5 because any number that ends in 5 is divisible by 5.
The numbers that are divisible by 35 are infinite. The first four are: 35, 70, 105, 140 . . .
if you mean wich numbers are not divisable by 4: 35 416 7235 1856 3720 Then: 35 and 7235 are not divisible by 4.
Yes: 140 / 4 = 35
if the number formed by the last two digits is divisible by 4, then the whole number will be divisible by 4 for example, 932 is divisible by 4 because 32 is divisible by 4 19935 is not divisible by 4 because 35 is not divisible by 4 (note: if the last two digits are 00, the number is divisible by 4)
35 is not divisible by 3.
35 is divisible by 5 because any number that ends in 5 is divisible by 5.
The numbers that are divisible by 35 are infinite. The first four are: 35, 70, 105, 140 . . .
Yes, evenly 5 times. 35 is also divisible by: 1, 5 and 35.
By the rules of divisibility, you know that 35 is divisible by 1 and 5 and not divisible by 2, 3, 4 and 6. Dividing those two numbers into 35 gives you 7 and 35. That makes the factors of 35 (1, 5, 7, 35) Now pair them up. (35,1)(7,5)
35
There are no such numbers. The only number in the range that is divisible by 35 is 70 and that is not divisible by 9.
753 is not divisible by 35. The factors of 753 are 1, 3, 251, 753.
No. To be divisible by 6 the number must be divisible by both 2 and 3. To be divisible by 2, the last digit of the number must be even (ie one of {0, 2, 4, 6, 8}). The last digit of 35 is 5 which is not even and so 35 is not divisible by 2. To be divisible by 3, sum the digits of the number and if this sum is divisible by 3 then so is the original number. As the test can be applied to the sum, repeatedly summing the digits of the sums until a single digit remains, then the original number is divisible by 3 only if this single digit is one of {3, 6, 9}. For 35 3 + 5 = 8 which is not divisible by 3 (nor is is one of {3, 6, 9}, thus 35 is not divisible by 3. As 35 is not divisible by both 2 and 3 (in fact it is divisible by neither 2 nor 3) it is not divisible by 6.