No, they are not. Each is divisible by 3.
A number that is divisible by 2, 3, 4, 5, 6, 8, 9, and 10 must be divisible by the least common multiple (LCM) of these numbers. The LCM of 2, 3, 4, 5, 6, 8, 9, and 10 is 360. Therefore, any multiple of 360 will be divisible by all of these numbers.
360
Yes it is. If you divide 360 by 5, you would get 72.
The least common multiple of all of these numbers is 360. This is the smallest number that is divisible by all five numbers. Any whole number multiple of 360 will also be divisible by all five numbers, so:2 x 360 = 7203 x 360 = 10804 x 360 = 1440, etc.
Being divisible by 2 and 3: 354 (and 360 if inclusive)Trick:Numbers divisible by 2 always ends with an even number (2,4,6,8,0)So: numbers divisible by 2 strictly between 350 and 360: 352, 354, 356, 358Numbers divisible by 3 have the sum of the digits add up to 3,6,9,12 and so onSince there are only 4 numbers there, just try them one by one352: 3+5+2=10 (not divisible by 3)354: 3+5+4=12 (divisible by 3)356: 3+5+6=14 (not divisible by 3)358: 3+5+8=16 (not divisible by 3)354/2=177354/3=118
No, they are not. Each is divisible by 3.
They are both divisible by 3, 5 and 15.
6, 9, 12, 30, 60, 90, 360, 690, 930, or (162,591). Here's a secret: If the sum of a number's digits is divisible by 3, then the number is divisible by 3. That's how you can tell quickly that 162,591 is divisible by 3.
Multiples of 360.
A number that is divisible by 2, 3, 4, 5, 6, 8, 9, and 10 must be divisible by the least common multiple (LCM) of these numbers. The LCM of 2, 3, 4, 5, 6, 8, 9, and 10 is 360. Therefore, any multiple of 360 will be divisible by all of these numbers.
90, 180, 270, 360
No. 360 is not evenly divisible by 32.
360
360
Yes
It is a TRUE statement.