no, because it has a 2 at the end. if the last digit in the number is an even number, then it is not a Prime number. Also if the only factors of the number is 1 and itself then it is a prime number. example 1: 5,622 = not prime number.... example 2: 13=prime number because the only factors are 1 and 13.
No. It is a factor but is not a prime number, being 2 x 7. Prime factors are 2 x 2 x 2 x 7 x 7
The prime factorization of 392 is 2 x 2 x 2 x 7 x 7 or 23 x 72.392= 2x2x2x7x7
They are: 2^3 times 7^2 = 392
To find the greatest common multiple of 392 and 112, we first need to find the prime factorization of each number. 392 = 2^3 * 7^2 and 112 = 2^4 * 7. Then, we take the highest power of each prime factor that appears in both numbers, which is 2^3 * 7 = 56. Therefore, the greatest common multiple of 392 and 112 is 56.
392
392 is composite. All whole numbers ending in two are composite except for the number 2 itself, which is prime.
392 is a composite number. A prime number has only 2 factors which are 1 and itself. Composite numbers are everything else except 1 and 0. 1 and 0 are neither prime, nor composite.
The prime factors of 392 are 2, 2, 2, 7, and 7. To find the prime factors, you divide 392 by the smallest prime number (2) until you cannot divide evenly. The factors of 392 are 1, 2, 4, 7, 8, 14, 28, 49, 56, 98, 196, and 392. These are all the numbers that can divide evenly into 392.
No it is not. A prime number is only divisible by 1 and itself, whereas 784 is at least divisible by the number 2 as well. 784/2=392
No, you can tell by the last digit being divisible by two, that the number is divisible by two. Thus it's composite.
No. It is a factor but is not a prime number, being 2 x 7. Prime factors are 2 x 2 x 2 x 7 x 7
2 × 2 × 2 × 7 × 7
The prime factorization of 392 is 2 x 2 x 2 x 7 x 7 or 23 x 72.392= 2x2x2x7x7
392 = 2^3 * 7^2 so the square factors are 4 and 49.
392 = 2 x 2 x 2 x 7 x 7.
They are: 2^3 times 7^2 = 392
2 x 2 x 2 x 7 x 7 = 392