0
No. It is a Prime number, so its only factors are 1 and 3.
What else can I help you with?
How do you factor -3m -3?
0
What is the HCF of 3 and 0?
The highest common highest common factor of 3 & 0 is 0 as 0 is has no value.
How do you factor 3x3-3x2-48x-60 equals 0?
3x3 -3x2 - 48x - 60 = 0 simply factor out a 3... 3(x3 - x2 - 16x - 20) = 0
Which number is NOT a factor of 300 5 8 6 20?
8. 300 ends in 0 or 5, so 5 is a factor 300 is divisible by 4 and 5, so 20 is a factor 300 is even and 3 + 0 + 0 = 3, so 6 is a factor Leaving 8 to be the non factor Testing if 8 is a factor: 4 x 3 + 2 x 0 + 0 = 12; 4 x 0 + 2 x 1 + 2 = 4 which is not 8, so 300 is not divisible by 8.
How do you find all the factors for a number without listing them all?
It is not simple. The only systematic way is to find the prime factorisation of the number and write it in exponential form. So suppose n = (p1^r1)*(p2^r2)*...*(pk^rk) where p1, p2, ... pk are prime numbers and rk are the indices (or powers). Then the factors of n are (p1^s1)*(p2^s2)*...*(pk^sk) where 0 ≤ sk ≤ rk. And remember that anything raised to the power 0 is 1. Example: n = 72 = 2*2*2*3*3 = (2^3)*(3^2) so, the factors of n are (2^a)*(3^b) where a = 0, 1, 2 or 3 and b = 0, 1 or 2. When (a, b) = (0, 0) the factor is 1. (a, b) = (1, 0) the factor is 2. (a, b) = (2, 0) the factor is 4. (a, b) = (3, 0) the factor is 8. (a, b) = (0, 1) the factor is 3. (a, b) = (1, 1) the factor is 6. (a, b) = (2, 1) the factor is 12. (a, b) = (3, 1) the factor is 24. (a, b) = (0, 2) the factor is 9. (a, b) = (1, 2) the factor is 18. (a, b) = (2, 2) the factor is 36. (a, b) = (3, 2) the factor is 72.
How do you factor -3m -3?
0
What is the HCF of 3 and 0?
The highest common highest common factor of 3 & 0 is 0 as 0 is has no value.
How do you factor 3x3-3x2-48x-60 equals 0?
3x3 -3x2 - 48x - 60 = 0 simply factor out a 3... 3(x3 - x2 - 16x - 20) = 0
Which number is NOT a factor of 300 5 8 6 20?
8. 300 ends in 0 or 5, so 5 is a factor 300 is divisible by 4 and 5, so 20 is a factor 300 is even and 3 + 0 + 0 = 3, so 6 is a factor Leaving 8 to be the non factor Testing if 8 is a factor: 4 x 3 + 2 x 0 + 0 = 12; 4 x 0 + 2 x 1 + 2 = 4 which is not 8, so 300 is not divisible by 8.
How do you find all the factors for a number without listing them all?
It is not simple. The only systematic way is to find the prime factorisation of the number and write it in exponential form. So suppose n = (p1^r1)*(p2^r2)*...*(pk^rk) where p1, p2, ... pk are prime numbers and rk are the indices (or powers). Then the factors of n are (p1^s1)*(p2^s2)*...*(pk^sk) where 0 ≤ sk ≤ rk. And remember that anything raised to the power 0 is 1. Example: n = 72 = 2*2*2*3*3 = (2^3)*(3^2) so, the factors of n are (2^a)*(3^b) where a = 0, 1, 2 or 3 and b = 0, 1 or 2. When (a, b) = (0, 0) the factor is 1. (a, b) = (1, 0) the factor is 2. (a, b) = (2, 0) the factor is 4. (a, b) = (3, 0) the factor is 8. (a, b) = (0, 1) the factor is 3. (a, b) = (1, 1) the factor is 6. (a, b) = (2, 1) the factor is 12. (a, b) = (3, 1) the factor is 24. (a, b) = (0, 2) the factor is 9. (a, b) = (1, 2) the factor is 18. (a, b) = (2, 2) the factor is 36. (a, b) = (3, 2) the factor is 72.
Is 7002 divisible by 3?
No... because 10 is not a factor of 3. 7+0+0+2= 10
What values of x will make the polynomial 0 if its factors are x - 6 and x - 3?
If a polynomial has factors x-6 and x-3 it will equal 0 if either factor equals 0 since the other factor then would be multiplied by 0. ie. 0 * (x-6)=0 and 0 * (x-3)=0. so x=3 or 6
Is 3 a factor of 45?
Yes, 3 is a factor of 45 because 45 is divisible by 3. 45 = 3 x 15 + 0.
Find the solution x2-9 equals?
To solve the equation ( x^2 - 9 = 0 ), you can factor it as ( (x - 3)(x + 3) = 0 ). Setting each factor equal to zero gives the solutions ( x - 3 = 0 ) or ( x + 3 = 0 ). Therefore, the solutions are ( x = 3 ) and ( x = -3 ).
How do you solve 5x2 plus 15x equals 0?
5x^(2) + 15x = 0 Factor Factor our '5x' Hence 5x(x - 3) = 0 Hence it follows that 5x = 0 Therefore x = 0 or the other multiplicand x - 3 = 0 x = 3 So the answer is x = 0 or x = 3 (two answers).
What are the solutions for 3x2 -9x?
To find the solutions for the equation (3x^2 - 9x = 0), we can factor it as (3x(x - 3) = 0). Setting each factor equal to zero gives us the solutions: (3x = 0) or (x - 3 = 0). Thus, the solutions are (x = 0) and (x = 3).
How do you factor x squared -2x-3 equals 0?
x squared -2x-3 equals 0 is the same as (x + 1)(x - 3) = 0
