Because not all odd numbers are multiples of 3 - I have shown you below that this is the case and you can see some multiples of 3 are even and some are odd and you can also see that there are even and odd numbers BETWEEN the multiples of 3. 1 (odd) 2 (even) 1*3 =3 (odd) 4 (even) 5 (odd) 2*3 = 6 (even) 7 (odd) 8 (even) 3*3 = 9 (odd) 10 (even) 11 (odd) 4*3 = 12 (even)
Alternating. 1 2 3 4 5 6 7 8 9 in row 3, (7,8,9) the 8 is even and the 7 and 9 are odd. thus odd,even,odd. in column 3, (3,6,9) the 6 is even and the 3 and 9 are odd, thus odd,even,odd. as the row/column selector (3) is odd the first digit in that row/column of a 3X3 grid will be odd as will the first. the numbers then alternate even odd even.
because... odd+odd=even even+odd=odd e.g 1+1+1=3 odd+odd+odd=odd
There is no solution to this problem. If each digit can be used once only then we have 5 odd numbered digits (1,3,5,7,9) and 4 even numbered digits (2,4,6,8). To create the two numbers that are added together requires the following combinations of digits. 5 Odd & 1 Even ....when added these will generate 2 Even digits & 1 Odd digit but the remaining digits are 3 Even. 4 Odd & 2 Even. These will generate 3 Even digits OR 1 Even digit & 2 Odd digits but the remaining digits are 1 Odd & 2 Even. 3 Odd & 3 Even. These generate 3 Odd digits OR 2 Even & 1 Odd digits but the remaining digits are 2 Odd & 1 Even. 2 Odd & 4 Even. These generate 3 Even digits OR 2 Odd & 1 Even digits but the remaining digits are 3 Odd & no Even.
3 odd numbers can't be equal to 50 because: odd number + odd number = even number even number + odd number = odd number thus, adding 3 odd numbers will always give a sum which is an odd number too even number.
Odd. Even + Even = Even Odd + Odd = Even Odd + Even = Even + Odd = Odd
No -an odd and an odd equals even ( 5+3=8) -an even and an odd equals odd (2+3=5) -an even and an even equals even (4+6=10)
Because not all odd numbers are multiples of 3 - I have shown you below that this is the case and you can see some multiples of 3 are even and some are odd and you can also see that there are even and odd numbers BETWEEN the multiples of 3. 1 (odd) 2 (even) 1*3 =3 (odd) 4 (even) 5 (odd) 2*3 = 6 (even) 7 (odd) 8 (even) 3*3 = 9 (odd) 10 (even) 11 (odd) 4*3 = 12 (even)
Alternating. 1 2 3 4 5 6 7 8 9 in row 3, (7,8,9) the 8 is even and the 7 and 9 are odd. thus odd,even,odd. in column 3, (3,6,9) the 6 is even and the 3 and 9 are odd, thus odd,even,odd. as the row/column selector (3) is odd the first digit in that row/column of a 3X3 grid will be odd as will the first. the numbers then alternate even odd even.
No, only every other multiple is odd. Example: 3,6,9,12,15,18
5.3333
because... odd+odd=even even+odd=odd e.g 1+1+1=3 odd+odd+odd=odd
The multiples of all odd numbers are odd and even. Odd x odd = odd. Odd x even = even. Since odd and even numbers alternate, the multiples will alternate as well.
the answer is even 3+1 = 4 3+3=6
No it is not possible to get a even number by adding odd and even number. 1+2=3-odd number.3+4=7-odd number.
opposite - answer will always be odd (when adding odd + even) odd + even 5 + 4 = 9 odd even + even 2 + 6 = 8 even odd + odd 3 + 1 = 4 even
There is no solution to this problem. If each digit can be used once only then we have 5 odd numbered digits (1,3,5,7,9) and 4 even numbered digits (2,4,6,8). To create the two numbers that are added together requires the following combinations of digits. 5 Odd & 1 Even ....when added these will generate 2 Even digits & 1 Odd digit but the remaining digits are 3 Even. 4 Odd & 2 Even. These will generate 3 Even digits OR 1 Even digit & 2 Odd digits but the remaining digits are 1 Odd & 2 Even. 3 Odd & 3 Even. These generate 3 Odd digits OR 2 Even & 1 Odd digits but the remaining digits are 2 Odd & 1 Even. 2 Odd & 4 Even. These generate 3 Even digits OR 2 Odd & 1 Even digits but the remaining digits are 3 Odd & no Even.